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Tamiku [17]
4 years ago
12

Mrs Grey is buying decorative ribbon of three different colors: blue, silver, and yellow. Blue ribbon is sold in rolls of 15 met

ers, silver is sold in rolls of 12 meters, and yellow comes in rolls of 20 meters. She needs to have the same length of each ribbon. What is the smallest number of rolls of each type that she should buy?
Mathematics
1 answer:
olganol [36]4 years ago
3 0

Answer:

4 rolls of blue ribbon,

5 rolls of silver ribbon,

3 rolls of yellow ribbon.

Step-by-step explanation:

We have been given that Mrs Grey is buying decorative ribbon of three different colors: blue, silver, and yellow. Blue ribbon is sold in rolls of 15 meters, silver is sold in rolls of 12 meters, and yellow comes in rolls of 20 meters.

As Mrs. Grey needs to have same length of each ribbon, so we will find the least common multiple of 15, 12 and 20.

Multiples of 15 are: 15, 30, 45, 60, 75, 90,...

Multiples of 12 are: 12, 24, 36, 48, 60, 72, 84,...

Multiples of 20 are: 20, 40, 60, 80,100,...

We can see that 60 is the least common multiple of 15, 12 and 20.

\text{The smallest number of rolls of blue ribbon}=\frac{60}{15}=4

Therefore, Mrs. Grey should buy 4 rolls of blue ribbon.

\text{The smallest number of rolls of silver ribbon}=\frac{60}{12}=5

Therefore, Mrs. Grey should buy 5 rolls of silver ribbon.

\text{The smallest number of rolls of yellow ribbon}=\frac{60}{20}=3

Therefore, Mrs. Grey should buy 3 rolls of yellow ribbon.

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What are the missing numbers?
kupik [55]

Answer:

You can use the formula 500 * 1.03^x to solve for any year.

year 4 is 500 * 1.03^(4) = 562.75

year 6 is 500 * 1.03^(6) = 597.03

Year 7 is 500 * 1.03^(7) = 614.94

Step-by-step explanation:

The amount is increasing, and there are two main ways for that to happen.  Addition and multiplication.  So let's see if it keeps getting the same amount added or multiplied.  

0 to 1 goes from 500 to 515, so 15 is added.  but 15.45 is added from 1 to 2, so we can't just do simple addition.

using multiplication 0 to 1 has 1.03 multiplied.  if you multiply by it again you do get 530.45, so we have established what is happening.  

You can use the formula 500 * 1.03^x to solve for any year.

so year 4 is 500 * 1.03^(4) = 562.75

year 6 is 500 * 1.03^(6) = 597.03

Year 7 is 500 * 1.03^(7) = 614.94

5 0
3 years ago
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fiasKO [112]

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Five added to the product of six and a number is seventeen.

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Step-by-step explanation:

I factored -5a out of 5a -5a^2-10a^4

hope this helped you

3 0
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Answer: 6.534 x 10^(-1)

Step-by-step explanation:

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Convert to decimal

6534/10000=0.6534

Then convert to standard form

0.6534=6.534 x 10^(-1)

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I hope this is correct and I hope that it helps

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