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Irina18 [472]
2 years ago
10

Which two of these can be stored in a float variable? 1 C 3.4 true "hello"

Computers and Technology
2 answers:
ruslelena [56]2 years ago
7 0

Answer:

3.4

Explanation:

A float variable can only store a floating-point number which means it can store a number that has a decimal place or a decimal number.

e-lub [12.9K]2 years ago
6 0

Answer:

Its 1 and C because it just is and that all oncan say so yea.yhank i

Explanation:

u

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Write a program whose inputs are three integers, and whose output is the smallest of the three values.
denis-greek [22]

Answer:

<h2>JAVA program: </h2>

import java.util.Scanner;  //Scanner class is used to get the input

public class FindSmallest // class to find the smallest of 3 integer values

{     public static void main(String[] args) //entry point of the main program

{  int number1, number2, number3;  // 3 integer type numbers are declared

       Scanner scanner = new Scanner(System.in); //

//new Scanner is an object that is pointing towards scanner to get the input

       System.out.println("Enter the first number:");

//prompts the user to enter the first integer value

       number1 = scanner.nextInt();

// nextInt() method of reads integer value entered by user

       System.out.println("Enter the second number:");

//prompts the user to enter the second integer value

       number2 = scanner.nextInt();

       System.out.println("Enter the third number:");

//prompts the user to enter the third integer value

       number3 = scanner.nextInt();

       scanner.close();         //closes scanner

   if( number1 <= number2 && number1 <= number3)

//checks the condition if number1 is less than or equal to number2 and //number3

           System.out.println(number1 + " is the smallest number");

// if condition is true then displays the messages number1 is the smallest

       else if (number2 <= number1 && number2 <=number3)

//else checks if number2 is less than or equal to number1 and number3

           System.out.println(number2 + " is the smallest number");

// if else condition is true then display that number2 is the smallest

       else

           System.out.println(number3 + " is the smallest number");    }  }

//else display number3 is the smallest.

<h2>C++ program</h2>

#include <iostream>

//includes iostream header file for input output functions

using namespace std;

//namespace is used by computer in order to detect cout endl cin. objects

int main() //start of the main program

{  int number1, number2, number3; //declares 3 integer type numbers

   cout << "Enter the first number: ";

//prompts user to enter 1st integer value

   cin >> number1;

//accepts the first input value

   cout << "Enter the second number: ";

   cin>> number2;

   cout << "Enter the third number: ";

   cin>> number3;

   if(number1 <= number2 && number1 <= number3)

/*if condition checks whether value stored in number1 is less than or equal to the values stored in number2 and number3 variables */

   { cout << number1<< " is the smallest number ";    }

//if the condition is true this means number1 is the smallest

   else if(number2 <= number1 && number2 <= number3)

/*if number1 is neither smaller than number2 nor number then program control will move to else if part which checks if number2 is less than or eqal to number1 and number3*/

   { cout << number2<< " is the smallest number ";    }

//true if else part means that number2 is the smallest

   else

    { cout << number3<< " is the smallest number ";    }}

/*in case none of the above conditions is true then else part will be exectued which means that number3 is the smallest */

<h2>Python Code</h2>

number1 = int(input("Enter the first number: "))

#prompts user to enter the first number

number2 = int(input("Enter the second number: "))

number3 = int(input("Enter the third number: "))

if (number1 <= number2) and (number1 <= number3):

#if condition checks whether value stored in number1 is less than or equal #to the values stored in number2 and number3 variables

  smallest = number1

#value of number1 will be stored in smallest if the condition evaluates to #true

elif (number2 <= number1) and (number2 <= number3):

#if number1 is neither smaller than number2 nor number then program #control will move to elif part(else if) which checks if number2 is less than #or equal to number1 and number3

  smallest = number2

#value of number2 will be stored in smallest if the elif condition evaluates #to true

else:

#in case none of the above conditions is true then else part will be #exectued which means that number3 is the smallest

  smallest = number3

#value of number3 is stored in smallest variable

print(smallest, "is the smallest number")

#smallest value stored in smallest variable is displayed as output

<h2>Explanation:</h2>

So the program is used to take three integers from the user. Next the if condition first compares number1 to number2 and number3. If number1 is less than or equals to both number2 and number3 this means that one is the smallest of the three values. If not then the else if condition will be checked. This condition checks if value in number2 variable is less than or equal to that of number1 and number3. If its true then this means that number2 is the smallest. If both if and else if conditions are false then this means that number3 is the smallest number. I have used less than or equal = to here along with the less than relative operator. The reason is that if the user enters number1 as 8 number2 as 8 and number3 as 9 then this means number1 and number2 are equal but less than number3 so the output will display 8 as the smallest number but without using = it will display 9 as the smallest number.

<h2>Output:</h2>

Enter the first number:

3

Enter the second number:

6

Enter the third number:

1

1 is the smallest number

6 0
4 years ago
Walter’s health insurance premium increased by 22 percent this year. Now he pays $488 every month for health insurance. What was
ElenaW [278]

Answer:

$380.64

Explanation:

So he what you do is take $488 multiply it by 22% to get $107.36 you then subtract $488 from $107.36 to get what he was paying before premium increase which is $380.64

7 0
4 years ago
3. A vulnerability is: a. A hacker searching for open ports b. A known attack method c. An incorrectly implemented policy d. All
ELEN [110]

Answer:

A

Explanation:

A hacker searching for open ports denotes vulnerability of computer (to hacking).

Cheers

7 0
3 years ago
Write an application that prompts a user for two integers and displays every integer between them. Display There are no integers
olga2289 [7]

Answer:

x = int(input("Enter an integer: "))

y = int(input("Enter another integer: "))

if x > y:

   for number in range(y+1, x):

       print(number, end=" ")

elif y > x:

   for number in range(x+1, y):

       print(number, end=" ")

else:

   print("There are no integers between {} and {}".format(x, y))

Explanation:

*The code is in Python.

Ask the user to enter the two integers, x and y

Since we want our program to run regardless of which entered value is larger, we need to compare the numbers to be able to create the loop that prints the numbers.

Check if x is greater than y. If it is, create a for loop that iterates from y+1 to x-1 and print the numbers

Otherwise, check if y is greater than x. If it is, create a for loop that iterates from x+1 to y-1 and print the numbers

If none of the previous part is executed, print that there are no integers between

4 0
3 years ago
Do the pros of interpersonal communication via social media outweigh the cons? Explain.
JulijaS [17]
Well in my opinion is that yes they do. The ability to be able to communicate with others so far way really helps society advance towards the future. And i cant stress of how the benefits of being able to share ideas with well anyone is so wonderful.

I hope this helps.
6 0
3 years ago
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