What are the zeroes of the function f(x)= 5x^2-25x/x

Choose the graph that represents the equation y=3[x+1]+1.

MatroZZZ [7]

Answer:

Step-by-step explanation:

Discussion

You haven't given us any choices. Always do that it you have them. Look for the graph that looks like the one below. It has the following characteristics

It opens upward
It lowest point is -1,1
y never equals zero
The y intercept is 0,4

7 0

2 years ago

A rectangle has a height of 43 and a width of 3x + 1.

fomenos

A = 43 • 3x + 1
= 44 •3x
= 132x

6 0

2 years ago

Read 2 more answers

Multiply: (3x - 5)(-x + 4)

insens350 [35]

Answer:

-3x²+17x-20

Step-by-step explanation:

When you apply the distributive property (which you did correctly), you simply multiply each number or variable in which you have to distribute it to (which again you wrote correctly) and then you add them all together.

(3x)(-x)=-3x²

+

(3x)(4)=12x

+

(-5)(-x)=5x

+

(-5)(4)=-20

Add those and you will get your answer. Hope this helped :)

3 0

2 years ago

Read 2 more answers

Two statistics teachers both believe that each has the smarter class. To put this to the test, they give the same final exam to

SVETLANKA909090 [29]

Answer:

We conclude that there is no difference between the two classes.

Step-by-step explanation:

We are given that two statistics teachers both believe that each has a smarter class.

A summary of the class sizes, class means, and standard deviations is given below:n1 = 47, x-bar1 = 84.4, s1 = 18n2 = 50, x-bar2 = 82.9, s2 = 17

Let $\mu_1$ = mean age of student cars.

$\mu_2$ = mean age of faculty cars.

So, Null Hypothesis, $H_0$ : $\mu_1=\mu_2$ {means that there is no difference in the two classes}

Alternate Hypothesis, $H_A$ : $\mu_1\neq \mu_2$ {means that there is a difference in the two classes}

The test statistics that will be used here is Two-sample t-test statistics because we don't know about the population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t_n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean age of student cars = 8 years

$\bar X_2$ = sample mean age of faculty cars = 5.3 years

$s_1$ = sample standard deviation of student cars = 3.6 years

$s_2$ = sample standard deviation of student cars = 3.7 years

$n_1$ = sample of student cars = 110

$n_2$ = sample of faculty cars = 75

Also, $s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(47-1)\times 18^{2}+(50-1)\times 17^{2} }{47+50-2} }$ = 17.491

So, the test statistics = $\frac{(84.4-82.9)-(0)}{17.491 \times \sqrt{\frac{1}{47}+\frac{1}{50} } }$ ~ $t_9_5$

= 0.422

The value of t-test statistics is 0.422.

Now, the P-value of the test statistics is given by;

P-value = P( $t_9_5$ > 0.422) = From the t table it is clear that the P-value will lie somewhere between 40% and 30%.

Since the P-value of our test statistics is way more than the level of significance of 0.04, so we have insufficient evidence to reject our null hypothesis as our test statistics will not fall in the rejection region.

Therefore, we conclude that there is no difference between the two classes.

6 0

2 years ago

What would be the answer for part a, b, and c?

denis-greek [22]

For part A :draw 5 separate rectangles, then draw 4 sections in each separate rectangle. Finally, shade in one of the the four pieces in each of the 5 rectangles.

For part B : Jareld wants to give his 5 candy bars with his friends. Each friend wants to get 1/4 of a candy bar. How many people will share the 5 candy bars using the facts provided?

For part C : (So whenever you do division between any type of fraction,whole number or mixed number) you do the strategy keep change flip where first you keep the fraction 5/1 which equals 5 as a whole number. Then you change the division symbol in the provided equation to a multiplication symbol (x). Then you flip the fraction 1/4 to 4/1. Then you plug in all of the numbers into your new and improved statement. 5/1 * 4/1=y. Y=20
Answer: 20 people

5 0

2 years ago