Question

during a science lab, Carina measured the mass of an object to be 23.4 grams. the actual mass turned out to be 22.5 grams. What was the percent error in Carina's measurement?

Answer 1

Answer:

formula for percent error (P): the absolute value of the actual observed value (A) minus the expected value (E) all divided by the expected value (E) multiplied by 100

$P = |\frac{A-E}{E}|$ x 100

plugging in those values would give us 3.85% when rounded to two decimal places