Answer:
Step-by-step explanation:
Answer: 99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week
//0.20113,0.20887[/tex]
Step-by-step explanation:
<u>step 1:-</u>
Given sample size n=200
of the 200 employed individuals surveyed 41 responded that they did work at home at least once per week
Population proportion of employed individuals who work at home at least once per week P = 
Q=1-P= 1-0.205 = 0.705
<u>step 2:-</u>
Now 
=0.0015
<u>step 3:-</u>
<u>Confidence intervals</u>
<u>using formula</u>


=0.20113,0.20887[/tex]
<u>conclusion:</u>-
99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week
//0.20113,0.20887[/tex]
Answer:
a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

d.9
b) 
a.15
c) For this case we have the sample size n = 25 and the sample variance is
, the standard error can founded with this formula:

Step-by-step explanation:
Part a
For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

d.9
Part b
From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

And the sample variance for this case can be calculated from this formula:

a.15
Part c
For this case we have the sample size n = 25 and the sample variance is
, the standard error can founded with this formula:

Y=-1/2x+8
perpendicular means slope is opposite reciprocal so it would be -1/2
y=-1/2x+b
Plug in points and solve for b
B=8
Answer:
three hundred and eight five twenty sevenths