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erastova [34]
3 years ago
10

Can you delete your posts?

Mathematics
2 answers:
DerKrebs [107]3 years ago
6 0
I’d look in the help center but you can probably click on the 3 dots next to your post or contact an admin
ladessa [460]3 years ago
3 0
Pretty sure you click the three dots
You might be interested in
How to write an exponential function whose graph passes through the points (0, -6) and (-2, -54).
suter [353]
Work shown above! Answer is y = -6(1/3)^x
edit: at the bottom it says "be must be 1/3" I meant "b must be"

6 0
3 years ago
In a recent​ year, companies spent a total of $88.4 billion on​newspaper, television, and radio ads. The total amount spent on t
emmasim [6.3K]

Answer:

(a) amount spent on newspaper ads = $42.8 billion.

(b) amount spent on television ads = $37.2 billion.

(c) amount spent on radio ads = $8.4 billion.

Step-by-step explanation:

Let us denote amount spent on Newspaper ads by symbol N.

                       amount spent on Television ads by symbol T.

                       amount spent on Radio ads by symbol R.

  • Given Total amount spent on newspaper, television, and radio ads =

                   N + T + R = $88.4 billion  -------- [Equation 1]

  • Total amount spent on television and radio ads was only $2.8 billion more than the amount spent on newspaper ads alone is represented by the expression :

                   T + R = $2.8 + N   ---------- [Equation 2]

  • The amount spent on newspaper ads was $5.6 billion more than what was spent on television ads.

                       N = $5.6 + T ----------- [Equation 3]

Now, taking value of R from Equation 1 and Equation 2 respectively we get;

              R = $88.4 - T - N ------------ [Equation 4]

              R = $2.8 + N - T ------------- [Equation 5]

Equating and solving Equation 4 and 5 we get,

           $88.4 - T - N = $2.8 + N - T

            $88.4 - $2.8 = 2*N

    Hence, N = $42.8 billion.

Now putting value of N in Equation 3 we get T = $42.8 - $5.6 = $37.2 billion.

And at last putting values of N & T in Equation 1 we get,

               R = $88.4 - $37.2 - $42.8 = $8.4 billion .

<em>Therefore, amount spent on newspaper ads = $42.8 billion.</em>

<em>                   amount spent on television ads = $37.2 billion.</em>

<em>                   amount spent on radio ads = $8.4 billion.</em>

4 0
3 years ago
The product of two numbers is 40. If one of the numbers is 8/15, what is the other number?
Harman [31]
If one number is 8/15, you take the difference which 7/15.
5 0
3 years ago
The heights of 10 year old children has a normal probability distribution with mean of 54.6 inches and standard deviation of 5.7
Fofino [41]

Answer:

a) 0.69

The probability that a randomly selected 10-year old child will be more than 51.75 inches tall

P(X>51.75 ) = 0.6915

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

<em>Given mean of the Population = 54.6 inches</em>

<em>Given standard deviation of the Population = 5.7 inches</em>

<em>Let 'X' be the random variable of normal distribution</em>

Let 'X' = 51.75 inches

Z = \frac{x-mean}{S.D} = \frac{51.75-54.6}{5.7} = -0.5

<u><em>Step(ii):</em></u>-

<em>The probability that a randomly selected 10-year old child will be more than 51.75 inches tall</em>

<em>P(X>51.75 ) = P(Z>-0.5)</em>

                  = 1 - P( Z < -0.5)

                 =   1 - (0.5 - A(-0.5))

                =    1 -0.5 + A(-0.5)

               =    0.5 + A(0.5)    (∵A(-0.5)= A(0.5)

              =     0.5 +0.1915

              =  0.6915

<u><em>Conclusion</em></u>:-

<em>The probability that a randomly selected 10-year old child will be more than 51.75 inches tall</em>

<em>P(X>51.75 ) = 0.6915</em>

5 0
3 years ago
The CBS’ television show 60 Minutes has been successful for many years. That show recently had a share of 20, which means that a
xxMikexx [17]
Given:
p = 20% = 0.2, sample proportion
n = 5000, sample size.
Confidence level = 95%

The confidence interval is
(p - 1.96k, p + 1.96k)
where
k=\sqrt{ \frac{p(1-p)}{n} }=\sqrt{ \frac{0.2*0.8}{5000}} =0.00566

Therefore the 95% confidence interval is
(0.1943, 0.2057) = (19.4%, 20.6%)

Answer: The 95% confidence interval is (19.4%, 20.6%)
6 0
4 years ago
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