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stiv31 [10]
3 years ago
15

How many edges does a polyhedron with 8 faces and 12 vertices have?

Mathematics
2 answers:
Savatey [412]3 years ago
7 0

Answer:

18 edges

Step-by-step explanation:

v-e+f=2

number of vertices(12) - number of edges (18) + number of faces(8) = 2

lakkis [162]3 years ago
7 0

Answer:

Edges = 18

Step-by-step explanation:

We know that

v - e + f = 2

Where,

v = vertices

e = edge

f = faces

So,

12 - e + 8 = 2

20 - e = 2

20 - 2 = e

18 = e

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Took me a while, but just add 48 for every 2 minutes.

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If the perimeter of a square is 64mm then how long is each side?
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\bf \begin{array}{ccll}&#10;lawn&hours\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;\frac{1}{15}&\frac{1}{3}\\\\&#10;\frac{15}{15}&h&#10;\end{array}\implies \cfrac{\quad \frac{1}{15}\quad }{\frac{15}{15}}=\cfrac{\quad \frac{1}{3}\quad }{h}\implies \cfrac{1}{15}\cdot \cfrac{15}{15}=\cfrac{\quad \frac{1}{3}\quad }{\frac{h}{1}}&#10;\\\\\\&#10;\cfrac{1}{15}=\cfrac{1}{3}\cdot \cfrac{1}{h}\implies \cfrac{1}{15}=\cfrac{1}{3h}\implies 3h=15\implies h=\cfrac{15}{3}\implies h=5
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3 years ago
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