Question

Find the solution of the system of equations. 10x+10y=40 5x+3y=8

Answer 1

Answer:

x = -2 & y = 6

Step-by-step explanation:

$10x+10y=40$

$10x+10y+ -10y=40+-10y$

$10x=-10y+40$

$\frac{10x}{10} =\frac{-10y+40}{10}$

$x=-y+4$

$5x+3y=8$

$5(-y+4)+3y=8$

$-2y+20=8$

$-2y+20+-20=8+-20$

$-2y=-12$

$\div2$

$y=6$

$x=-y+4$

$x=-6+4$

$x=-2$

Hope this helps.