This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
Answer:
Step-by-step explanation:
3−4x/3 this is for x
y = -4/3x + 3 this is for why I’m not sure which one your trying to solve for
Area of circle = pi (d/2)^2
area of semi-circle =0.5* pi (d/2)^2
=0.5* pi (6/2)^2
=14.14
Answer:
y= (-7/16)
Step-by-step explanation:
Multiply (3/4)(1/4)= (3/16)
y= (3/16)-(5/8)
y= (-7/16)
I hope this is right, im not 100% sure