Answer:
<em>4</em><em>*</em><em>5x-7</em><em>=</em><em>20</em>
4*5(-7)-7=20
20(-7)-7=20
-140-7=20
-140=20+7
-140=27
=27+140
<u>=</u><u>167</u>
<em>-</em><em>3x</em><em>+</em><em>7</em><em>=</em><em>28</em>
-3(6)+7=28
-3(6)=28-7
-18=21
=21+18
<u>=</u><u>39</u>
<em>2x</em><em>+</em><em>3</em><em>=-7</em>
2(-5)+3=-7
2(-5)=-7-3
-10=-10
=-10+10
<u>=</u><u>0</u>
25 is the answer for number 3
Change 5/8 and 3/10 so they have the same denominator
5/8×5/5=25/40
3/10×4/4=12/40
25/40+12/40=37/40
5/8+3/10=37/40
Answer:
Let the ten's digit no. be x and one's digit no. be y.
So the no. will be = 10x+y.
Given : x+y=9-----(I)
9(10x+y)=2(10y+x) ⇒88x−11y=0 -----(II)
On solving I and II simultaneously you will get x=1 and y=8.
Therefore your desired no. is 18.
Step-by-step explanation:
Hope it is helpful.....