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Mashutka [201]
3 years ago
14

20) A test consists of 10 true/false questions. To pass the test a student must answer at least 6 questions correctly. If a stud

ent guesses on each question, what is the probability that the student will pass the test
Mathematics
1 answer:
jeka943 years ago
4 0

Answer:

50-50 chance I suppose (1/2 or 5/10) or 40% to 60% percent chance

Step-by-step explanation:

He can guess all of the questions and get all of them right, and it is a possibility that he can also get all of them wrong. So I say, 50-50. I can't lie, I'm having trouble with probability as we speak.

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Match each equation to its solution.
algol13

Answer:

<em>4</em><em>*</em><em>5x-7</em><em>=</em><em>20</em>

4*5(-7)-7=20

20(-7)-7=20

-140-7=20

-140=20+7

-140=27

=27+140

<u>=</u><u>167</u>

<em>-</em><em>3x</em><em>+</em><em>7</em><em>=</em><em>28</em>

-3(6)+7=28

-3(6)=28-7

-18=21

=21+18

<u>=</u><u>39</u>

<em>2x</em><em>+</em><em>3</em><em>=-7</em>

2(-5)+3=-7

2(-5)=-7-3

-10=-10

=-10+10

<u>=</u><u>0</u>

5 0
3 years ago
Read 2 more answers
I’m looking for number 3 on the picture attached
Nataliya [291]
25 is the answer for number 3
8 0
3 years ago
What is the sum of 5/8+3/10
FrozenT [24]
Change 5/8 and 3/10 so they have the same denominator

5/8×5/5=25/40

3/10×4/4=12/40

25/40+12/40=37/40



5/8+3/10=37/40
7 0
3 years ago
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CAN SOMEONE HELP ME PLEASE I NEED IT RIGHT NOW,​
wariber [46]

Answer:

2 one in rotation

3 in translation

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5 0
3 years ago
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If the sum of 2 digits no. is 9 and their differenc is 1 find te no.​
Pavlova-9 [17]

Answer:

Let the ten's digit no. be x and one's digit no. be y.

So the no. will be = 10x+y.

Given : x+y=9-----(I)

9(10x+y)=2(10y+x) ⇒88x−11y=0 -----(II)

On solving I and II simultaneously you will get x=1 and y=8.

Therefore your desired no. is 18.

Step-by-step explanation:

Hope it is helpful.....

4 0
3 years ago
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