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3 years ago

6 + -3 = 3t + 6 please help we find the solutions

Mathematics

2 answers:

Eva8 [605]3 years ago

7 0

Answer:

Basic fact:

a + and a - make a -

Step-by-step explanation:

6 + -3 = 3t + 6

6+-3=6-3

6-3=3

3= 3t+6

-6

-3=3t

divide by 3

-1=t

DiKsa [7]3 years ago

6 0

Answer:

t = -1

Step-by-step explanation:

6 + -3 = 3t + 6

Step One : Subtract 6 from both sides.

6 + -3 - 6 = 3t + 6 - 6

Step Two : Simplify.

3t = -3

Divide both sides by 3.

-3 divided by 3 is -1.

Therefore t is -1. Hope this helps, please mark brainliest if possible!

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4 years ago

8x^3+2x^2-8 estimate the relative maxima and relative minima

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3 years ago

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-BARSIC- [3]

Step-by-step explanation:

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3 years ago

Find the function y = f(t) passing through the point (0, 18) with the given first derivative.

monitta

Answer:

$\displaystyle y = \frac{t^2}{16} + 18$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Functions
Function Notation
Coordinates (x, y)

Calculus

Derivatives

Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

Point (0, 18)

$\displaystyle \frac{dy}{dt} = \frac{1}{8} t$

Step 2: Find General Solution

Use integration

[Derivative] Rewrite: $\displaystyle dy = \frac{1}{8} t\ dt$
[Equality Property] Integrate both sides: $\displaystyle \int dy = \int {\frac{1}{8} t} \, dt$
[Left Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \int {\frac{1}{8} t} \, dt$
[Right Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle y = \frac{1}{8}\int {t} \, dt$
[Right Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \frac{1}{8}(\frac{t^2}{2}) + C$
Multiply: $\displaystyle y = \frac{t^2}{16} + C$