Since:
ax(2x + y - 5) = 6x^2 +3xy - 15x,
we should factor X out of the second equation to find out the value of a:
6x^2 + 3xy - 15x =
x(6x + 3y - 15),
Now that we factored X out, to find a, we need to find the other common factor:
(6x + 3y - 15) / (2x + y - 5),
which is 3.
Hence the value of a is 3
Looking through my old calc notes, I am reading that f(x) needs to be continuous on [a,b] and f ' (x) also needs to be continuous on [a,b]. Both conditions are needed. If you had to pick just one, then I'd say f(x) being continuous is much more important. Though I'm not 100% sure on this one. My thinking is that if there was any discontinuities on f(x), then the arc length would be distorted and overblown. The arc length should not account for any piece that isn't on the curve.
The answer is D. 64. Have a nice day!
Alright - we want to start off by seeing if this number would be positive or negative. Debit means that you owe something, or that you have to pay that amount of money. If you had money to buy things with, that would be positive, but since debit means you haven’t paid something off yet, that is negative. Next, since you have 40 dollars in debt, you have -40 dollars.
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Least common multiple: factor them, then see what they have in common and what is leftover and multiply those expressions:
(x - 2)(x + 3) 10(x + 3)(x + 3)
Common: (x + 3)
Leftover: (x - 2), (10), (x + 3)
Common · Leftover is: (x + 3) · (x - 2) · (10) · (x + 3) = 10(x - 2)(x + 3)²
Answer: LCM is 10(x - 2)(x + 3)²
