First, find the slope of the line. Use the two points given, (-4,0) and (4,2), in the slope formula rise over run. The change in rise is 2 and the change in run is 8, meaning that the slope is 2/8, simplified to 1/4. The y-intercept is 1, shown by the graph and the dashed line and shaded area means that the inequality symbol must be <. Slope-intercept form is shown as y = mx + b, so after putting our information in to the equation the answer is y < 1/4x + 1. Hope this helps!
Y = -(1/2)(x-2)² +8
Re write it in standard form:
(y-8) = -1/2(x-2)² ↔ (y-k) = a(x-h)²
This parabola open downward (a = -1/2 <0), with a maximum shown in vertex
The vertex is (h , k) → Vertex(2 , 8)
focus(h, k +c )
a = 1/4c → -1/2 = 1/4c → c = -1/2, hence focus(2, 8-1/2) →focus(2,15/2)
Latus rectum: y-value = 15/2
Replace in the equation y with 15/2→→15/2 = -1/2(x-2)² + 8
Or -1/2(x-2)² +8 -15/2 = 0
Solving this quadratic equation gives x' = 3 and x" = 2, then
Latus rectum = 5
I dont think that it belongs in primary consumers, secondary or third level consumers
<span>v(x)=(s/t)
= (3x - 6) / (-3x+6)
= [3(x-2)] / [-3(x-2)] --> 3 is factored out
= 1/-1 </span>---> common terms are cancelled out.
= -1 ---> This is the
simplified formula.
To find the domain, we equate the denominator to 0.
-3x+6 = 0
3x = 6
x = 2
Domain: all values except 2.
w(x)=(t/s)(x)
= (-3x+6)x / (3x-6)
= [-3x(x-2)] / [3(x-2)] --> 3 is factored out
= -x --> The common terms are cancelled out. This is the simplified formula.
Solving for domain:
3x-6 = 0
3x = 6
x = 2
Domain: all values except 2.
