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Len [333]
2 years ago
5

What is the value of the expression below when x=7? 5x-3

Mathematics
2 answers:
Sladkaya [172]2 years ago
6 0

Answer:

\longmapsto 5x - 3

\longmapsto5(7) - 3

\longmapsto35 - 3

\longmapsto 32

The value of 5x-3 is 32 when x =7.

TEA [102]2 years ago
4 0

Answer:

The value of the expression is 382

Step-by-step explanation:

x = 77 and the expression given is 5x - 3

5x - 3

input the given

5(77) - 3

solve

5 times 77 is 385

so now we have

385 - 3 which equals 382

so our final answer is 382

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Which of the following demonstrates the Commutative Property of Multiplication?
vazorg [7]

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I think the is c 5(2a-3) = (2a - 3) . 5

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3 years ago
Is 7x=5x-25+30 no solution,one solution, or all real numbers? <br><br> Thank you!
viva [34]

One solution let's find that

\\ \rm\hookrightarrow 7x=5x-25+30

\\ \rm\hookrightarrow 7x=5x+5

\\ \rm\hookrightarrow 2x=5

\\ \rm\hookrightarrow x=5/2

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2 years ago
PLEASE HELP!! I beg of yall
Delicious77 [7]

Answer:oop

Step-by-step explanation:

5 0
2 years ago
Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.
fenix001 [56]

Answer:

The angle between vector \vec{u} = 5\, \vec{i} - 8\, \vec{j} and \vec{v} = 5\, \vec{i} + \, \vec{j} is approximately 1.21 radians, which is equivalent to approximately 69.3^\circ.

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

  • their dot products, and
  • the product of their lengths.

To be precise, if \theta denotes the angle between \vec{u} and \vec{v} (assume that 0^\circ \le \theta < 180^\circ or equivalently 0 \le \theta < \pi,) then:

\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}.

<h3>Dot product of the two vectors</h3>

The first component of \vec{u} is 5 and the first component of \vec{v} is also

The second component of \vec{u} is (-8) while the second component of \vec{v} is 1. The product of these two second components is (-8) \times 1= (-8).

The dot product of \vec{u} and \vec{v} will thus be:

\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}.

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both \vec{u} and \vec{v}:

  • \| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}.
  • \| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}.

<h3>Angle between the two vectors</h3>

Let \theta represent the angle between \vec{u} and \vec{v}. Apply the formula\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} to find the cosine of this angle:

\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}.

Since \theta is the angle between two vectors, its value should be between 0\; \rm radians and \pi \; \rm radians (0^\circ and 180^\circ.) That is: 0 \le \theta < \pi and 0^\circ \le \theta < 180^\circ. Apply the arccosine function (the inverse of the cosine function) to find the value of \theta:

\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ .

3 0
2 years ago
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