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2 years ago

If 4 bushels of oats weigh 112 kg, how much do 8. 5 bushels of oats weigh?.

Mathematics

2 answers:

Charra [1.4K]2 years ago

5 0

Answer:

238 kg

Step-by-step explanation:

If 4 bushels weight 112, then divide 112 by 4 and you get that each bushel weighs 28 kg. Now multiply that by 8.5.

rusak2 [61]2 years ago

3 0

Answer:

284 kgs

Step-by-step explanation:

4 bushels = 112 kg

8 bushels = 224 kg

PLUS

0.5 bushels = 60 kg

8.5 bushels = 224 + 60 = 284 kg

8.5 bushels of oats weighs 284 kgs.

Hope this helps! :)

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Olin [163]

Answer:

Step-by-step explanation:

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3 years ago

If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.

Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have $S_1=3\times2^{1-1}+2(-1)^1=3-2=1$ , which agrees with the initial value S₁ = 1.

• Assume the closed form is correct for all n up to n = k. In particular, we assume

$S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}$

and

$S_k=3\times2^{k-1}+2(-1)^k$

We want to then use this assumption to show the closed form is correct for n = k + 1, or

$S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}$

From the given recurrence, we know

$S_{k+1}=S_k+2S_{k-1}$

so that

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)$

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}$

$S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)$

$S_{k+1}=3\times2^k-2(-1)^k$

$S_{k+1}=3\times2^k+2(-1)(-1)^k$

$\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}$

which is what we needed. QED

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3 years ago

Only some of the students in the Level 1 swim lessons move up to Level 2 at the end of

larisa86 [58]

The list that orders the fractions from least to greatest is:

$\frac{7}{12}, \frac{2}{3}, \frac{17}{24}, \frac{3}{4}$

<h3>Ordering of fractions</h3>

To order the fractions from least to greatest, we have to realize their conversion to decimal.

To realize the conversion, the numerator is divided by the denominator, as ordering decimal numbers are easier than fractions.

Hence, the fractions converted to decimal are:

$\frac{2}{3} = 0.6667$ .

$\frac{7}{12} = 0.5833$ .

$\frac{17}{24} = 0.7083$

$\frac{3}{4} = 0.75$

Hence, the list from least to greatest is, according to the results of the conversions:

$\frac{7}{12}, \frac{2}{3}, \frac{17}{24}, \frac{3}{4}$

To learn more about ordering of fractions, you can take a look at brainly.com/question/26139168

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3 years ago

Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are sel

Andre45 [30]

Answer:

Step-by-step explanation:

Given

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$=0.489$

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$\dfrac{^{58}C_{6}}{^{64}C_{6}}$

$=0.54$

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3 years ago

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