Question

Admission to a baseball game is $4.00 for general admission and $5.50 for reserved seats. The receipts were $5973.50 for 1358 paid admissions. How many of each
ticket were sold? (Round to nearest Integer if necessary.)

Answer 1

Answer:

997 admission tickets were sold and 361 reserved seats were sold.

Step-by-step explanation:

There is a couple of ways to calculate this.

Multiply the cost of an admission ticket by the total paid admissions:

$4 \times 1358 = 5432$

Subtract this from the total cost:

$5973.5 - 5432 = 541.5$

Divide the above value by the difference between the cost of the two tickets:

$5.5 - 4 = 1.5$

$541.5 \div 1.5 = 361$

Now we know the number of general admission tickets, we can subtract the cost of this from the total cost:

$361 \times 5.5 = 1985.5\\5973.50 - 1985.5 = 3988$

Divide this by the cost of general admission:

$3988 \div 4 = 997$

So there were 997 admission tickets sold and 361 reserved seats sold.

Hope this helps!