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klemol [59]
2 years ago
10

Find the length s of the arc of a circle radius 40 miles subtended by the central angle 1/8 radian

Mathematics
1 answer:
Mrac [35]2 years ago
5 0
\bf \textit{arc's length}\\\\
s=r\theta \quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad radians\\
------\\
r=40\\
\theta =\frac{1}{8}
\end{cases}\implies s=40\cdot \cfrac{1}{8}\implies s=5
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insens350 [35]

Answer:

P - Q = - 11b² + 8b - 4

Step-by-step explanation:

P - Q

= - 4b² + 6b - 9 - (7b² - 2b - 5) ← distribute parenthesis by - 1

= - 4b² + 6b - 9 - 7b² + 2b + 5 ← collect like terms

= - 11b² + 8b - 4

5 0
2 years ago
A group of students wanted to investigate the claim that the average number of text messages sent yesterday by
Likurg_2 [28]
First we need to write the null and alternate hypothesis for this case.

Let x be the average number of text message sent. Then

Null hypothesis: x = 100
Alternate hypothesis: x > 100

The p value is 0.0853

If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.

If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.

If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
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7 0
3 years ago
What is HL???<br><br> HL=__<br><br> Image Below
Advocard [28]

Consider a trapezoid GJKF with:

GH=JH (hypothesis)

FL=KL (hypothesis)

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so: HL=1/2(2.5+1.2)=1.85

4 0
2 years ago
a company uses two vans to transport workers from a free parking lot to the workplace between 7:00 and 9:00 am . one van has 6 m
olganol [36]
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y + 2x = 57 

2y - 2x =12
y + 2x = 57 

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4 0
3 years ago
Read 2 more answers
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
ddd [48]

Answer:

f'(x) = 4x^2 - 3 for x \le -3

Step-by-step explanation:

See attachment for proper question

Given

f(x) = -\frac{1}{2}\sqrt{x + 3}

For

x \ge -3

Required

Determine the inverse function

f(x) = -\frac{1}{2}\sqrt{x + 3}

Replace f(x) with y

y = -\frac{1}{2}\sqrt{x + 3}

Swap the positions of x and y

x = -\frac{1}{2}\sqrt{y + 3}

Multiply both sides by -2

-2 * x =-2 *  -\frac{1}{2}\sqrt{y + 3}

-2x =\sqrt{y + 3}

Square both sides

(-2x)^2 =(\sqrt{y + 3})^2

4x^2 =y + 3

Make y the subject

y = 4x^2 - 3

The inverse has been solved. So, we need to replace y with f'(x)

f'(x) = 4x^2 - 3

Next, is to determine the interval

x \ge -3

Change inequality to \le

x \le -3

Hence, the inverse function is:

f'(x) = 4x^2 - 3 for x \le -3

7 0
3 years ago
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