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AfilCa [17]
2 years ago
12

In which region would an archaeologist be most likely to find evidence of roman roads?.

SAT
1 answer:
kolezko [41]2 years ago
3 0

Answer:

saharan africa

Explanation:

. Roman roads are spread to northern Africa.

if the archeologist would go to sub Sahara Africa, he would be more likely to fijd the roads.

he could also go to Israel. the Roman's made a stone paved road and some people while traveling it dropped coins. if he were to look for the coins, he would find the road.

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Use the sample data and confidence level given below to complete parts a through d.
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Using the information given and the z-distribution, it is found that:

a) The point estimate of the population proportion is 0.5544.

b) The margin of error is: 0.0320.

c) The interval is: (0.5224, 0.5864).

d) The interpretation of the interval is: we are 95% sure that the true population proportion is between 0.5224 and 0.5864.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions has the bounds given by the rule presented as follows:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which the variables used to calculated these bounds are listed as follows:

  • \pi is the point estimate of the population proportion.
  • z is the critical value.
  • n is the sample size.

The confidence level is of 95%, hence the critical value z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

From the sample, the sample size and the point estimate are given as follows:

n = 929, \pi = \frac{515}{929} = 0.5544

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 1.96\sqrt{\frac{0.5544(0.4456)}{929}}

M = 0.0320.

The interval is the point estimate plus/minus the margin of error, hence:

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More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

4 0
1 year ago
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