Do what you are doing in class but make up your own real-life situations
Let the number of red, black, green and blue balls be R, B, G, U respectively.
B=R (There are as many black balls as red balls)
G+R=10 so G=10-R (Green balls and red balls should add up to 10)
R+10=U (There should be 10 more blue balls than red balls)
The minimal number of balls is 2, 304 so we have the following inequality:
R+B+G+U≥ 2,304
R+(R)+(10-R)+ (R+10)≥2,304
4R≥2,304
R≥2,304/4=576 so R=576
Answer: 576
Answer:
we have the equation y = (1/2)*x + 4.
now, any equation that passes through the point (4, 6) will intersect this line, so if we have an equation f(x), we must see if:
f(4) = 6.
if f(4) = 6, then f(x) intersects the equation y = (1/2)*x + 4 in the point (4, 6).
If we want to construct f(x), an easy example can be:
f(x) = y = k*x.
such that:
6 = k*4
k = 6/4 = 3/2.
then the function
f(x) = y= (3/2)*x intersects the equation y = (1/2)*x + 4 in the point (4, 6)
Answer:
1
Step-by-step explanation:
to get at least 50% you would have to add 1 more marble
