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2 years ago

Write an equation in slope-intercept form that describes the line through the points (-2,6) and (3, 1).

Mathematics

1 answer:

vladimir1956 [14]2 years ago

3 0

Answer:

y=-x+4

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(1-6)/(3-(-2))

m=-5/(3+2)

m=-5/5

m=-1

y-y1=m(x-x1)

y-6=-1(x-(-2))

y-6=-(x+2)

y-6=-x-2

y=-x-2+6

y=-x+4

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4 is the square root of which number ?

Tom [10]

Your answer would be two

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3 years ago

A service club is selling raffle tickets for 2.50 each to raise money for a charity. Vanessa has 34.75 to spend on raffle ticket

posledela

Answer:

13 Raffle tickets

Step-by-step explanation:

Cost for one riffle ticket = 2.50

Total money of Vanessa budgeted for riffle ticket : 34.75

Greatest number of riffle ticket, venessa can with with 34.75

I'll like us to divide 34.75 by 2.5 to get the exact value.

Therefore,

34.75 / 2.5

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3 years ago

How do you find a vector that is orthogonal to 5i + 12j ?

Rashid [163]

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\$

$\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}$

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

$\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}
\\\\\\
\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}
\\\\\\
\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}$

4 0

3 years ago

What is the value of x? - 40 - 70 - 140 - 160

Lilit [14]

70
because the little lines on the lines mean that the bottom two angles are the same
180-40=140
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3 years ago

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katen-ka-za [31]

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