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Sonbull [250]
2 years ago
14

i a stoc kcar model is built to scale of 1 cm : 2.5 ft and the model measures 7.7 cm in length, what will be the length of actua

l stock car?
Mathematics
1 answer:
Oksanka [162]2 years ago
3 0

Answer:

19.25 ft

Step-by-step explanation:

for every one cm the actual car is 2.5 feet. therfore it would be 7.7 times 2.5 which equals 19.25

You might be interested in
What is the least common multiple of 8 and 11
tino4ka555 [31]

Answer:

88

Step-by-step explanation:

Find the prime factorization of both 8 and 11.

8 → 4 × 2 → 2 × 2 × 2

11 → 11

Then, multiply each factor the greater number of times it occurs. Since no factors are duplicated between 8 and 11 (as in, 2 is not a factor of 11, nor is 11 a factor of 8), LCM will equal 2 × 2 × 2 × 11.

2 × 2 × 2 × 11 = 88, so the LCM is 88.

It's a little hard to explain without visuals. A video could be useful, though I can't put links here.

7 0
3 years ago
HELPPP KE PJEASE. ASAPPPP ITS FOR A QUIZZZ
san4es73 [151]
=(1/2) * 2 * 3.2 + (1/2) *2 * 3.2 + (1/2) * 2 * 4 + (1/2) * 2 * 4
= 2 * 3.2 + 2 * 4
= 2 * (3.2 + 4)
= 2 * 7.2
= 14.4 sq feet
2 * 14.4 = 28.8 sq feet
8 0
2 years ago
Mary’s trapezoid-shaped garden has a perimeter of 24 yd. She knows the length of three of the sides, 3 yd, 6 yd, and 9 yd.
Anna007 [38]

Answer:

6

Step-by-step explanation:

to find the perimeter of a trapezoid you add all the sides together

therefore we do it backwards

24-3-6-9=6

6 0
2 years ago
Read 2 more answers
I need Help please!!
PSYCHO15rus [73]
I think it’s A because the s is between P&Q and S&C if it’s wrong I’m sorry!
3 0
3 years ago
A diagnostic test for a disease is such that it (correctly) detects the disease in 90% of the individuals who actually have the
Ne4ueva [31]

Answer:

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Test positive

Event B: Has the disease

Probability of a positive test:

90% of 3%(has the disease).

1 - 0.9 = 0.1 = 10% of 97%(does not have the disease). So

P(A) = 0.90*0.03 + 0.1*0.97 = 0.124

Intersection of A and B:

Positive test and has the disease, so 90% of 3%

P(A \cap B) = 0.9*0.03 = 0.027

What is the conditional probability that she does, in fact, have the disease

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.027}{0.124} = 0.2177

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

3 0
3 years ago
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