Question

In order to clear out room for new merchandise, james decided to mark down some of the items for sale in his electronics store. He marked down dvd players by 36%, and he marked down stereo tuners by 22%. If dvd players cost $41. 60 after the markdown and stereo tuners cost $69. 42 after the markdown, which item’s price was reduced by more, and by how many dollars more was it reduced? round all dollar values to the nearest cent. A. The dvd player’s price was reduced by $3. 82 more than the stereo tuner’s price. B. The dvd player’s price was reduced by $27. 82 more than the stereo tuner’s price. C. The stereo tuner’s price was reduced by $0. 29 more than the dvd player’s price. D. The stereo tuner’s price was reduced by $27. 53 more than the dvd player’s price.

Answer 1

The dvd player’s price was reduced by $3. 82 more than the stereo tuner’s price.

• Let the cost price of dvd players be D.

• Let the cost price of stereo tuners be S.

Given the following data:

• Markdown for dvd player = 36%

• Markdown for stereo tuner = 22%

• Markdown cost for dvd player = $41.60

• Markdown cost for stereo tuner = $69.42

To determine which item’s price was reduced by more, and by how many dollars:

First of all, we would calculate the cost price of each item.

For dvd players:

Note: You'll pay 64% since it was markdown by 36%.

$\frac{64}{100} \times D = 41.60\\\\64D=41.60 \times 100\\\\64D=4160\\\\D=\frac{4160}{64}$

D = $65

Reduction: Dvd player = $65-41. 60=$ $23.40

For stereo tuners:

Note: You'll pay 78% since it was markdown by 22%.

$\frac{78}{100} \times S = 69.42\\\\78S=69.42 \times 100\\\\78S=6942\\\\S=\frac{6942}{78}$

D = $89

Reduction: Stereo tuner = $89-69. 42=$ $19.58

Now, we can calculate the difference in reduction of the cost price of both items:

$Difference = 23.4 -19.58$

Difference = $3.82

Therefore, the price of the dvd players was reduced by $3. 82 more than the price of the stereo tuners.

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