9514 1404 393
Answer:
BC = 5
Step-by-step explanation:
Of course, this geometry program can tell you the length of BC.
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If you follow directions, you get a right triangle BCF that has leg lengths 3 and 4. The Pythagorean theorem then tells you the length of hypotenuse BC is ...
BF = 4 -1 = 3
FC = 4 -0 = 4
BC² = BF² +FC²
BC² = 3² +4² = 9 +16 = 25
BC = √25
BC = 5
ANSWER FOR UR QUESTION!
Graph
Find f(f(x))
Describe the Transformation
Find the Domain of the Composition f(f(x))
Solve for x
Solve the System of Equations
Find the Area Between the Curves
Solve by Graphing
Answer:
(-2, -4.5)
Step-by-step explanation:
First picture)
I: 5x+2y=-4
II: -3x+2y=12
add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2
insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3
(-2,3)
question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs
insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults
insert adults into II:
33-8=childs
25=childs
so it's the last option
question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6
so it's the last option
question 8)
I: x+y=12
II: x-y=6
subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3
insert y into I:
x+3=12
x=9
(9,3)
question 9)
I: x+y=6
II: x=y+5
if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6
which is the second option :)
Answer:
c≈15.07
Step-by-step explanation:
c=a2+b2=11.12+10.22≈15.07481
