<span>Authorizing technologies are technologies that controls the use of system and network resources through authentication and authorization.
</span><span>Enabling technologies are innovation technologies that drive radical change in the capabilities of a user or culture.
</span>Obstructing technologies include blocking<span> and filtering, content manipulation, attacks.
</span>Preemption means "prior seizure of" and preemptive technologies <span>take control of the operating system from one task and giving </span>it<span> to another task.
</span><span>Technologies that function within the established system are called enabling technologies.</span>
Answer:
Explanation:
There are many weaknesses/vulnerabilities, some of which are the following...
Default Network Hardware, many individuals will go out and buy a new router and install it in their home. These devices come with a preset configuration including a preset security password which is many times a default password used for every router of the same model. This can be easily obtained by anyone who can then access the network.
Access Point hacking, an experienced individual can use a packet sniffer to detect the SSID that is frequently sent from the router in order to create an access point to be able to access the network.
WEP encryption is another vulnerability. These are very low security passwords that can be cracked using different software in a short period of time.
These are some of many vulnerabilities that wireless local networks have, but there are also many precautions and security measures that can be taken to prevent them.
Answer:
Code is too large , i attached a source file below and also a text file from where i get Questions
Explanation:
Answer:
def leap_year(y):
if y % 4 == 0:
return 1
else:
return 0
def number_of_days(m,y):
if m == 2:
return 28 + leap_year(y)
elif m == 1 or m == 3 or m == 5 or m == 7 or m == 8 or m ==10 or m == 12:
return 31
elif m == 4 or m == 6 or m == 9 or m == 11:
return 30
def days(m,d):
if m == 1:
return 0 + d
if m == 2:
return 31 + d
if m == 3:
return 59 + d
if m == 4:
return 90 + d
if m == 5:
return 120 + d
if m == 6:
return 151 + d
if m == 7:
return 181 + d
if m == 8:
return 212 + d
if m == 9:
return 243 + d
if m == 10:
return 273 + d
if m == 11:
return 304 + d
if m == 12:
return 334 + d
def days_left(d,m,y):
if days(m,d) <= 60:
return 365 - days(m,d) + leap_year(y)
else:
return 365 - days(m,d)
print("Please enter a date")
day=int(input("Day: "))
month=int(input("Month: "))
year=int(input("Year: "))
choice=int(input("Menu:\n1) Calculate the number of days in the given month.\n2) Calculate the number of days left in the given year.\n"))
if choice == 1:
print(number_of_days(month, year))
if choice == 2:
print(days_left(day,month,year))
Explanation:
Hoped this helped
Answer:
PROGRAM QuadraticEquation
Solver
IMPLICIT NONE
REAL :: a, b, c
;
REA :: d
;
REAL :: root1, root2
;
//read in the coefficients a, b and c
READ(*,*) a, b, c
WRITE(*,*) 'a = ', a
WRITE(*,*) 'b = ', b
WRITE(*,*) 'c = ', c
WRITE(*,*)
// computing the square root of discriminant d
d = b*b - 4.0*a*c
IF (d >= 0.0) THEN //checking if it is solvable?
d = SQRT(d)
root1 = (-b + d)/(2.0*a) // first root
root2 = (-b - d)/(2.0*a) // second root
WRITE(*,*) 'Roots are ', root1, ' and ', root2
ELSE //complex roots
WRITE(*,*) 'There is no real roots!'
WRITE(*,*) 'Discriminant = ', d
END IF
END PROGRAM QuadraticEquationSolver