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2 years ago

10

If you roll a fair 10-sided die 7 times, what is the probability that the die lands on "10" exactly 2 times?

1 answer:

nexus9112 [7]2 years ago

7 0

Answer: 2:7 times

Step-by-step explanation: hope it helps u

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ElenaW [278]

Answer:

-1 and -3

(n+7)(n-8)

Step-by-step explanation:

1. Find the Zeros

$f(x)=x^{2} +4x+3$

$f(x)=\left(x+1\right)\left(x+3\right)$

$x+1=0\\x=-1\\x+3=0\\x=-3$

2. Factoring Trinomials

$f(x)=n^{2} -n-56$

$f(x)=\left(n+7\right)\left(n-8\right)$

$n+7=0\\n=-7\\n-8=0\\n=8$

4 0

3 years ago

Can someone help me please?

Zinaida [17]

I think the answer is c sorry if I’m wrong

6 0

3 years ago

Divide <br> 8 2/5 ÷ (-2 1/5)

lesantik [10]

8 2/5 ÷(-2 1/5) = -3.81818181818

6 0

3 years ago

What is the next number? 2+3=8 3+7=27 4+5=32 5+8=60 6+7=72 7+8=?

ale4655 [162]

Answer:

<h2>7 + 8 = 98</h2>

Step-by-step explanation:

2 + <em>3</em> = <u>8</u>

<u>8</u> : 2 = 4; 4 - 1 = <em>3 (subtract 1)</em>

3 + <em>7</em> = <u>27</u>

<u>27</u> : 3 = 9, 9 - 2 = <em>7 (subtract 2)</em>

4 + <em>5</em> = <u>32</u>

<u>32</u> : 4 = 8; 8 - 3 = <em>5 (subtract 3)</em>

5 + <em>8</em> =<u>60</u>

<u>60</u> : 5 = 12, 12 - 4 = <em>8 (subtract 4)</em>

6 + <em>7</em> = <u>72</u>

<u>72</u> : 6 = 12, 12 - 5 = <em>7 (subtract 5)</em>

7 + <em>8</em><em> </em>= <u>x</u>

<u>x</u> : 7 = y, y - 6 = <em>8 (subtract 6)</em>

Solve:

y - 6 = 8 <em>add 6 to both sides</em>

y - 6 + 6 = 8 + 6

y = 14

<u>x</u> : 7 = y ⇒ <u>x</u> : 7 = 14 ⇒ <u>x</u> = (14)(7) ⇒ <u>x</u> = 98

8 0

3 years ago

Graph y−5=−2/3(x+9) using the point and slope given in the equation.

pishuonlain [190]

Answer:

(-1.5, 0), (0, -1)

4 0

4 years ago

Read 2 more answers