The graph represents the fees in thousands of dollars, y, depending on the amount invested in millions, x, with one financial in
vestment firm.
Over what interval is the change constant?
[0, 5)
[1, 5)
[0, 20)
[1, 20)
Over what interval is the change constant?
[0, 5)
[1, 5)
[0, 20)
[1, 20)
1 answer:
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Answer:
The rate at which the distance between the two people is changing 15 seconds later is 7.28 ft/sec.
Step-by-step explanation:
Here, we note the following
Let the person walking way fom the elevator be X
Let the other person going up in the elevator be Y
Therefore after 15 seconds, their positions will be;
For X, 2 ft/sec × 15 s = 30 ft away from the elevator
For Y, 7 ft/sec × 15 s = 105 ft up in the elevator
At that instant, the distance between them is given as
d² = x² + y²
= 30² +105² = 11925 ft²
d = √11925 ft² = 109.202 ft
The rate of change of the distance between the two peopl, X and Y is given as
Therefore, or
Since is given as 2 ft/sec and
= 7 ft/sec
Then
Answer: x = 12
<u>Step-by-step explanation:</u>
a) Linear Pair: 110° + ∠a = 180° --> ∠a = 70°
b) congruent sides implies congruent angles --> ∠b = 70°
c) Triangle Sum Theorem: ∠a + ∠b + ∠c = 180
70° + 70° + ∠c = 180°
∠c = 40°
d) Complimentary Angles: ∠c + ∠d = 90°
40° + ∠d = 90°
∠d = 50°
∠2) Linear Pair: ∠d + ∠2 = 180°
50° + ∠2 = 180°
∠2 = 130°
x) m∠2 = 130°
10x + 10 = 130°
10x = 120
x = 12
