Question

If 36 Superscript 12 minus m Baseline = 6 Superscript 2 m, what is the value of m? 4 6 8 9.

Answer 1

The value of m is 6.

Power

A power denotes the number of times a number is been multiplied by itself. For example,

6² = 6 x 6 = 36,

4³ = 4 x 4 x 4 = 64

2³ = 2 x 2 x 2 = 8

(4²)³ = $4^{2\times 3}$ = $4^6$ = $4\times 4\times 4\times 4\times 4\times 4$ = 4096

Given to us,

$36^{(12-m)}=6^{2m}$

As we know 6²=36, thus we can write it as,

$36^{(12-m)}=6^{2m}\\6^{2(12-m)}=6^{2m}$

As the bases on both the sides are equal, comparing the order(power) of both the sides,

$2(12-m)=2m\\12-m = m\\12 =m+m\\2m=12\\m=\frac{12}{2}=6$

Hence, the value of m is 6.

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Answer 2

Answer:

m = 6

Step-by-step explanation:

$36^{12-m}=6^{2m}\\\\36^{12-m}=(6^{2})^{m}\\\\\36^{12-m}=36^{m}$

Bases are equal. so, compare the powers

12 - m = m

12 = m +m

12 = 2m

12/2 = m

6 = m

m = 6