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Basile [38]
3 years ago
5

Write the equation of the line that goes through the

Mathematics
1 answer:
Anarel [89]3 years ago
5 0

Answer:

y = 5/2x -3

Step-by-step explanation:

Perpendicular lines have slopes that are negative reciprocals of one another

so slope is 5/2

Using (0,-3) => y = 5/2x + b

-3 = 5/2(0) + b

b = -3

y = 5/2x -3

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Solve the following system by graphing. If there​ isn't a unique solution to the​ system, state the reason. y=-2x y=2x+4
natka813 [3]

Answer:

We have the system of equations:

y = -2*x

y = 2*x + 4.

To solve it by graphing, you need to graph both lines and see in which point the lines intersect each other.

You can see it in the image below. (blue is y = 2*x + 4, and green is y = -2*x)

We also can calculate the solution with math, let's do that:

y = -2*x

y = 2*x + 4.

We can replace the first equation in the second one, to get:

-2*x = 2*x + 4

Now let's solve this for x

-2*x -2*x = 4

-4*x = 4

x = 4/-4 = -1

Evaluating this in one of the equations we get:

y = -2*-1 = 2

Then the solution is the point (-1, 2), exactly what we can see in the graph.

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3 years ago
5-9(-5)= <br> Please help with strategy please ... i need to know how to get the answer
Semmy [17]

Answer:

50

Step-by-step explanation:

Simplify the expression.

hope this helps

7 0
3 years ago
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Given that lim x→1 (5x − 3) = 2, illustrate definition 2 by finding values of δ that correspond to ε = 0.1, ε = 0.05, and ε = 0.
kow [346]
\displaystyle\lim_{x\to1}(5x-3)=2

is to say that for any \varepsilon>0, we can find \delta>0 such that 0 implies |(5x-3)-2|.

To that end, we have

|(5x-3)-2|=|5x-5|=5|x-1|

which means that if \varepsilon=0.1 is given, then we can choose \delta=\dfrac{0.1}5=0.02; if \varepsilon=0.05, then \delta=\dfrac{0.05}5=0.01; if \varepsilon=0.01, then \delta=\dfrac{0.01}5=0.002.
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Triangle d is similar
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The inequality 6-2/3x
steposvetlana [31]

........The answer is A

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