Is the following relation a function {(-6,-3),(-6,-1),(-6,5),(-6,8)

Mathematics

1 answer:

Inga [223]3 years ago

8 0

Answer:

Step-by-step explanation:

This relation (this group of points) is NOT a function. In order to be a function, every x-value (the first number in the pair) can only be paired up with one y-value (only one partner for the x)

In this relation, -6 is paired up with four different y-values (four different partners!)

If you plotted these points on a graph, you would see they are all lined up in a vertical line. If you have learned about the vertical line test, you will see that a vertical line goes through all four points. This set of points fails the vertical line test. To be a function, a vertical line can only touch the points one at a time.

To be a function, every x can only have one y partner.

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andre [41]

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3 0

3 years ago

If x-1/x=5 find x^3+1/x^3=?

ipn [44]

$\dfrac{x-1}{x}=5\ \ \ \ /x\neq0\\\\\dfrac{x-1}{x}=\dfrac{5}{1}\ \ \ \ |\text{cross multiply}\\\\5x=x-1\ \ \ \ |-x\\\\5x=1\ \ \ \ |:5\\\\x=0.2\\\\\dfrac{x^3+1}{x^3}=\dfrac{x^3}{x^3}+\dfrac{1}{x^3}=1+\dfrac{1}{x^3}\to1+\dfrac{1}{0.2^3}=1+\dfrac{1}{0.008}\\\\=1+\dfrac{1}{\frac{8}{1,000}}=1+\dfrac{1,000}{8}=1+125=126\\\\\text{Answer:}\ \dfrac{x^3+1}{x^3}=126$