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3 years ago

I NEED TO KNOW WHAT THIS IS PLEASE HELP ASAP

Mathematics

1 answer:

Karolina [17]3 years ago

8 0

Answer:

this is a counting template

Step-by-step explanation:

brain cells

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PLEASE HELP QUICK 100 POINTS

MrRissso [65]

Answer:

Change per week: $20

Starting amount of money: $550

Step-by-step explanation:

Given equation:

$y=550+20x$

where:

x = number of weeks
y = total account balance

Change per week

As the variable x represents the number of weeks, its coefficient represents the change per week in the amount of money.

Therefore, the change per week in the amount of money in the account is $20.

Initial Balance

The starting amount of money in the account (initial balance) will be the value of y when x = 0:

$\implies y=550+20(0)=550$

Therefore, the starting amount of money in the account is $550.

4 0

2 years ago

Corey bought 2 1/2 liters of paint for$60 what was the cost per liter of paint.

hichkok12 [17]

2 1/2 is also 2.5, therefore to calculate each liter, just 60/2.5, so the answer is $24

8 0

3 years ago

Read 2 more answers

Help please i’m not really sure what the answer is

Maslowich

Answer:

The area is 48

The perimeter is 32

4 0

3 years ago

A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y

siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32

Given that 100 beetles are released into a field.

So that means initial number of beetles P=100

Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

$A=P(1+r)^n$ where A is number of beetles at any year n.

Plug the given values into above formula we get:

$A=100(1+0.32)^n$

$A=100(1.32)^n$

now plug n=10 years

$A=100(1.32)^{10}=100(16.0597696605)=1605.97696605$

Hence answer is approx 1606 beetles will be there after 20 years.

Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

$A=100(1.32)^{20}=100(257.916201549)=25791.6201549$

Hence answer is approx 25791 beetles will be there after 20 years.

Now we have to find time for 100000 beetles so plug A=100000

$A=100(1.32)^n$

$100000=100(1.32)^n$

$1000=(1.32)^n$

$log(1000)=n*log(1.32)$

$\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n$

33.174666862=n

Hence answer is approx 33 years.

4 0

4 years ago

Read 2 more answers

Factor wheels show all the

Zielflug [23.3K]

answer: 2 × 2 × 2 × 2 × 2 = 32

Step-by-step explanation:

$32 \\ = 16 \times 2 \\ = 4 \times 4 \times 2 \\ = 2 \times 2 \times 2 \times 2 \times 2$

3 0

2 years ago