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jolli1 [7]
3 years ago
11

HELP ASAP 50 POINTS

Mathematics
1 answer:
serg [7]3 years ago
7 0
<h3>Part A</h3>

<u>Factoring the area:</u>

  • 4x² + 20x + 25 =
  • (2x)² + 2*2x*5 + 5² =
  • (2x + 5)²

<u>The length of the side is:</u>

  • √(2x + 5)² =
  • 2x + 5
<h3>Part 2</h3>

<u>Factoring the area:</u>

  • 4x² − 9y²=
  • (2x)² - (3y)² =
  • (2x + 3y)(2x - 3y)

<u>The sides of the rectangle are:</u>

  • 2x + 3y and 2x - 3y
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There are 10 clown noses in a package the whole package is 6.99 what are the clown noses individually worth?
zalisa [80]

Answer:

Step-by-step explanation:

This is 1.42 or if u want a perfect rounded answer it would be 1.43 for each nose if the package was 7 dollars

6 0
3 years ago
Read 2 more answers
A airplane travels 600 kilometers in 2.5 hours.What is the speed of the plane?
Vitek1552 [10]

Answer:

To solve this one, simply use the equation (600/2.5)=(x/1)

then solve for x. that will give you the speed in kilometers per hour

7 0
4 years ago
S) Suppose that a local second hand store is selling grab bags for $20 each in order to get rid of excess stock. They have creat
mestny [16]

Answer:

Step-by-step explanation:

Hello!

a)

The variable of interest is

X: monetary value of a grab bag. ($)

The possible values this variable can take are:

X: 15; 40; 60; 120

To calculate the relative frequency of each possible value of the variable you have to divide the number of times this value is observed by the total of observations (sample size)

There where a total of 300 bags created, from these, 40 cost $40, 20 cost $60, 1 cost $120, and the rest have a monetary value of $15.

There are then 300- (40+20+1)= 239 bags with a monetary value of $15

The frequencies for each value of X are:

X= 15 ⇒ p(X)= 239/300= 0.797

X= 40 ⇒ p(X)= 40/300= 0.133

X= 60 ⇒ p(X)= 20/300=0.067

X= 120⇒ p(X)= 1/300= 0.003

The probability distribution for X is:

Xi: 15; 40; 60; 120

p(Xi):0.797; 0.133; 0.067; 0.003

∑p(Xi)= 0.797+0.133+0.067+0.003=1

b)

To calculate the mean you have to use the following formula:

E(X)= ∑Xp(X)= 15*0.797+40*0.133+60*0.067+120*0.003= 21.655≅ $21.7

c)

The standard deviation is the square root of the variance:

Variance:

V(X)= ∑X²p(X)-(∑Xp(X))²= 676.525 - (21.655)²= 207.585

∑X²p(X)= 15²*0.797+40²*0.133+60²*0.067+120²*0.003= 676.525

Standard deviation:

√V(X)= √207.585= $14.407= $14.41

d)

Considered the probability distribution, it is more likely to buy a $15 worth bag than any of the others, it is therefore not worthwhile to spend $20 in a bag full of merchandise worth $15.

I hope this helps!

5 0
3 years ago
How to solve this showing all work ! Also explain why they aren’t polynomials if you can :)
Lesechka [4]

Polynomials are linear combinations of positive integer powers. For example,

x^{100}+30x^2-\sqrt 2\,x+21

is a polynomial, but

-x^{-1}-4x^\pi+x^{3/2}

is not.

(In case you're unfamiliar with the term, a linear combination of two quantities is the sum of scaled versions of those quantities, e.g. a general linear combination of a and b is k_1a+k_2b, where k_1,k_2 are any numbers.)

8x^2-18\sqrt x+5x-3 is not a polynomial; the offending term is -18\sqrt x, or -18x^{1/2}.

7 0
3 years ago
Mr. Brown has taken out a loan of value $1,000 with a 5% APR. He has been paying off the loan at a constant rate of r = $150/yea
Dafna11 [192]

Answer:

\frac{dp}{dt} = 0.05P - 150

Step-by-step explanation:

Let P(t) be the balance of the loan at time t years,

Let P(t) will satisfy \frac{dp}{dt}=rP-R

where r = annual interest rate

          R = per year payment rate

          R = $150/year

          r = \frac{5}{100} = 0.05  \frac{5}{100}

Now we have the following picture,

Interest            Balance          Payment

5%           ⇒          P(t)       ⇒     $150/year

(0.05)

Therefore, a linear ODE satisfied by P(t) is given by

\frac{dp}{dt} = 0.05P - 150

6 0
3 years ago
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