HELPPP please I forgot how-

Mathematics

1 answer:

PtichkaEL [24]2 years ago

3 0

Answer:

min: 8

max:28

med: 22

1st quartile: 12

3rd quartile: 26

hope this helps :)))

Step-by-step explanation:

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Find the measure of the largest angle in ABC if a = 12, b = 8 and c = 13.

Papessa [141]

Answer:

$C=78.28^{\circ \:}$

Step-by-step explanation:

We are given a triangle

whose sides are

a=12

b=8

c=13

Since, c is largest among them

So, angle C must be largest angle

we can find angle C

we can use law of cosine formula

$cos(C)=\frac{a^2+b^2-c^2}{2ab}$

now, we can plug values

$cos(C)=\frac{12^2+8^2-13^2}{2\times 12\times 8}$

$cos(C)=\frac{13}{64}$

now, we can find angle

we get

$C=78.28^{\circ \:}$

5 0

2 years ago

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Ulleksa [173]

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2 years ago

Answer true or false for 1-10 (picture above)

Softa [21]

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$7)\ \sqrt{100+64}=\sqrt{100}+\sqrt{64}\qquad FALSE\\\\8)\ \sqrt{30}=\sqrt{5\cdot6}=\sqrt5\cdot\sqrt6\qquad TRUE\\\\9)\ \sqrt{44}=\sqrt{22+22}=\sqrt{22}+\sqrt{22}\qquad FALSE\\\\10)\ \sqrt{10\cdot10}=\sqrt{10}\cdot\sqrt{10}\qquad TRUE$