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WARRIOR [948]
2 years ago
9

kayla and Jane helped Mr.John fit kids in the auditorium. There was 603 kids,and each row can fit 31 kids. How many rows do they

need to use?​
Mathematics
1 answer:
olga2289 [7]2 years ago
4 0

Answer:

Around 19 rows

Step-by-step explanation:603/31= 19.40 so I'm not too sure

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A $50 item was marked up 20%. What is the total increased cost of the item?​
GenaCL600 [577]

They increased it by $10.

It ended up costing $60.

Hope this helps.

4 0
3 years ago
State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should
Yuki888 [10]

Solving for <em>Angles</em>

\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A

* Do not forget to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

Solving for <em>Edges</em>

\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2

You would use this law under <em>two</em> conditions:

  • One angle and two edges defined, while trying to solve for the <em>third edge</em>
  • ALL three edges defined

* Just make sure to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under <em>three</em> conditions:

  • Two angles and one edge defined, while trying to solve for the <em>second edge</em>
  • One angle and two edges defined, while trying to solve for the <em>second angle</em>
  • ALL three angles defined [<em>of which does not occur very often, but it all refers back to the first bullet</em>]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0
2 years ago
Can you help me out with this question 5 pls
Maslowich
Gives an output of 1 I think
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2 years ago
What is the value of each number in 8,236,014,597?
Blababa [14]

Answer:

8 = billions

2 = hundred millions

3 = ten millions

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4 = thousands

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4 0
2 years ago
Read 2 more answers
Help for brainliest
Troyanec [42]

Answer:

sorry don't know but hope you have a amazing year

6 0
2 years ago
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