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3 years ago

What is the gradient of the graph shown? Give your answer in its simplest form.

Mathematics

1 answer:

Masja [62]3 years ago

8 0

Answer:

Step-by-step explanation:

Choose 2 points on the graph: (0, -2) and (1, 0)

$\boxed{ gradient = \frac{y _{1} - y_2 }{x_1 - x_2} }$

Gradient of graph

$= \frac{0 - ( - 2)}{ 1 - 0}$

$= \frac{0 + 2}{1}$

= 2

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the cost of fencing a rectangular field at rupees 30 per metre is rupees 2400 if the length of the its field is 24m than its bre

prohojiy [21]

Answer:

breadth = 8, length = 32

Step-by-step explanation:

perimeter = 2 x (length x breadth)

= 2 x ((24 + b) + b))

= 2 x (24 + 2b)

= 48 + 4 b

48 + 4b meters costs rupees 2400

each meter costs rupees 30

so,

30 x (48 + 4b) = 2400

1440 + 120b = 2400

120b = 960

b = 8

the breadth is 8m, the length is 8 + 24 = 32m

3 0

3 years ago

How do you do this?! (2w-1)/(4)=(2-w)

nikklg [1K]

Answer:

w = 3 is your answer.

Step-by-step explanation:

You want to get w by itself.

(2w - 1)/(4) = 2 - w You will add the w on both sides.

(3w - 1)/(4) = 2 You will multiply 4 on both sides.

3w - 1 = 8 You will add 1 on both sides.

3w = 9 You will divide 3 on both sides.

w = 3 is your answer.

6 0

3 years ago

Triangle RST has vertices located at R (2, 3), S (4, 4), and T (5, 0).

LiRa [457]

The length of the sides are 2.24, 4.24 and 4.12 units while the slope are 0.5, -1 and -4.

<h3>Linear equation</h3>

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

For RS:

$Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(4-3)^2+(4-2)^2}=2.24 \\
\\
slope=\frac{y_2-y_1}{x_2-x_1} =\frac{4-3}{4-2}=0.5$

For RT:

$Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(0-3)^2+(5-2)^2}=4.24 \\
\\
slope=\frac{y_2-y_1}{x_2-x_1} =\frac{0-3}{5-2}=-1$

For ST:

$Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(0-4)^2+(5-4)^2}=4.12 \\
\\
slope=\frac{y_2-y_1}{x_2-x_1} =\frac{0-4}{5-4}=-4$

The length of the sides are 2.24, 4.24 and 4.12 units while the slope are 0.5, -1 and -4.

Find out more on linear equation at: brainly.com/question/14323743

5 0

3 years ago

Can someone help me with this pls

Marina CMI [18]

Answer:

16 and 40

Step-by-step explanation:

Greater than 8,

The highest common factor is 8, the lowest common multiple is 80.

So, the two numbers are greater than 8, divisible by 8 ( highest common factor.)

The two numbers are 16 and 40.

Hope this helps plz mark brainliest :D

4 0

3 years ago

What number must you add to complete the square? x^2 + 2x = -1

Andru [333]

$\large\begin{array}{l} \textsf{You must add 1 to complete the square.}\\\\ \textsf{There is a very common special product: (square of a sum)}\\\\ \mathsf{(a+b)^2=a^2+2ab+b^2}\\\\\\ \textsf{Take the given equation:}\\\\ \mathsf{x^2+2x=-1\qquad(i)}\\\\\\ \textsf{The first term is a square (x squared)}\\\\ \textsf{The second term is a product of 2, x and 1.} \end{array}$

$\large\begin{array}{l}\\\\\\ \textsf{We need to find a proper value for b, so that if we add it to}\\\textsf{the left side of the equation, we get a perfect square.}\\\\ \textsf{So,}\\\\ \begin{array}{cccccccccc} \mathsf{a^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{a}&\!\!\!\cdot\!\!\!&\mathsf{b}&\!\!\!+\!\!\!&\mathsf{b^2}&=\mathsf{(a+b)^2}\\\\ \mathsf{\downarrow}&&&\!\!\!\!\!&\downarrow&\!\!\!\!\!&\downarrow&&\downarrow\\\\ \mathsf{x^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{x}&\!\!\!\cdot\!\!\!&\mathsf{1}&\!\!\!+\!\!\!&\mathsf{1^2}&=\mathsf{(x+1)^2} \end{array}\\\\\\ \textsf{Just by comparing the expressions above, we can conclude that}\\\textsf{b must be equal to 1, so we get a perfect square:}\\\\ \mathsf{(x+1)^2=x^2+2x+1} \end{array}$

$\large\begin{array}{l}\\\\\\ \textsf{Back to (i), adding 1 to both sides:}\\\\ \mathsf{x^2+2x+1=-1+1}\\\\ \boxed{\begin{array}{c} \mathsf{(x+1)^2=0} \end{array}} \end{array}$

$\large\begin{array}{l}\\\\\\ \textsf{If you want to solve this equation for x, you will find}\\\\ \mathsf{x+1=0}\\\\ \mathsf{x=-1}\quad\longleftarrow\quad\textsf{(solution)} \end{array}$

If you're having problems understanding the answer, try seeing it through your browser: brainly.com/question/2112248

$\large\begin{array}{l} \textsf{Any doubt? Please, comment below.}\\\\\\ \textsf{Best regards! :-)} \end{array}$

6 0

3 years ago

Read 2 more answers