<span>Data:
infinite geometric series
A1
= 880
r = 1 / 4
The sum of a geometric series in sigma
notation is:
n 1 - r^n
∑ Ai = A ----------- ; where A = A1
i = 1 1-r
When | r | < 1 the infinite sum exists and is equal to</span><span><span>:
∞ A
∑ Ai = ---------- ; where A = A1
i = 1 1 - r</span>
So, in this case</span><span><span>:
∞ 880
∑ Ai = -------------- = 4 * 880 / 3 = 3520 /3 = 1173 + 1/3
i = 1 1 - (1/4)</span> </span>
Answer: 1173 and 1/3
54/4.5 = 12
Set it up as long division, with 54 "inside" the division sign and 4.5 outside. Then you have to move the decimal on 4.5 to the right once, which will give you 45 on the outside. You also have to move the decimal over 1 more place on the 54, which will give you 540 on the inside. Then figure out how many times 45 can go into 54, which is once. Then subtract 45 from 54, which will give you 9. Then you are left with 90 on the inside and 45 goes into that 2 times.
Answer:
33p+58x
Step-by-step explanation:
Answer:
24
Step-by-step explanation:
5+7=12x2=24
Answer:
The answer is D
Step-by-step explanation:
