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Setler79 [48]
3 years ago
12

A plaintiff sues a defendant for injuries suffered when the plaintiff was struck by a car driven by a guest who was leaving the

defendant's house following a cocktail party. The plaintiff claims that the driver consumed too much liquor at the defendant's cocktail party and was noticeably drunk before leaving the party and injuring the plaintiff. The plaintiff offers evidence that, after the accident, the defendant visited the plaintiff at the hospital and, after offering to pay all of the plaintiff's medical expenses, said, "That's the least I can do after letting the guest leave my house so drunk last night."The statement that the guest was drunk when leaving the cocktail party on the night of the accident is __________.
Social Studies
1 answer:
Grace [21]3 years ago
7 0

Answer:

Admission

Explanation:

The fact that the defendant was drunk when he left the party was the sole cause of the accident. The reason the defendant was allowed to leave the party was not in moral standing, the fault of any. However, since the host of the party was aware that he was drunk and allowed him to leave does require that he assume some legal liability. In that same vein the host of the party was forward to the plaintiff to announce to him that he was aware of the circumstances.  This is not hearsay, but admission.

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<u>Explanation:</u>

As it is given there are four available colours of the car. That means we have 4 cars. 2 \times 4 =8. Now choose the first car. The no.of way of choosing the first car is equalled to 8 and imagine the first car Colour is black. Now we have a black car so we have to choose from 6 options apart from black.

Now no.of way of choosing the 2 car = 6 and imagine it is blue. Now we have to choose two colour car, so now we have 4 options to choose from. The no.of choosing the car = 4. Now let's calculate the total arrangement - 8 \times 6 \times 4=192. It is the total calculation for three cars.

But we have to know the selection so three cars can also be arranged in 6 ways. So the number of different combinations of three cars can be calculated as 192÷6= 32. This is how the selection is being done.

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