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ad-work [718]
3 years ago
8

Can someone help me on this?

Mathematics
1 answer:
jek_recluse [69]3 years ago
5 0

Answer:

381.05 ft

Step-by-step explanation:

A right triangle can be formed with the bottom of the tree, the top of the tree, and you. In a right triangle, for any angle θ, tanθ=opposite/adjacent.

Let h represent the height of the tree. The angle 60° has opposite side

Set up the following equation;

tan(60°)=h/220

Multiply both sides by 220:

h=220tan(60°)≈381.05 ft (rounded to the nearest hundredth, ans)

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lys-0071 [83]

Answer:

The roots of  equations are as m =  \frac{-3}{2} + \frac{\sqrt{11} }{2}  And n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}    

Step-by-step explanation:

The given quadratic equation is 2 x² + 6 x - 1 = 0

This equation is in form of a x² + b x + c = 0

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And products of roots = \frac{c}{a}

So, m + n = \frac{ - 6}{2} = - 3

And m × n =  \frac{ - 1}{2}

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Or, (m - n)² = 9 + 2 = 11

I.e m - n = \sqrt{11}

Again m + n = - 3    And m - n = \sqrt{11}

Solving this two equation

(m + n) + ( m - n) = - 3 + \sqrt{11}

I.e 2 m =  - 3 + \sqrt{11}

Or, m = \frac{-3}{2} + \frac{\sqrt{11} }{2}

Similarly n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}      

Hence the roots of  equations are as m =  \frac{-3}{2} + \frac{\sqrt{11} }{2}  And n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}      Answer

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