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pogonyaev
3 years ago
11

Which operation is the opposite of multiplication? A. Division B. Addition C. Summation D. Subtraction

Mathematics
2 answers:
svp [43]3 years ago
6 0
Division is the opposite of multiplication
Artyom0805 [142]3 years ago
6 0
A. division because subtraction is the opposite of addition and choice c is not 1 of the  4 operations.
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4 years ago
A total of 2n cards, of which 2 are aces, are to be randomly divided among two players, with each player receiving n cards. Each
klasskru [66]

Answer:

P(X_s^c|X_F) =0.2

P(X_s^c|X_F) =0.31

P(X_s^c|X_F) =0.331

Step-by-step explanation:

From the given information:

Let represent X_F as the first player getting an ace

Let X_S to be the second player getting an ace and

\sim X_S as the second player not getting an ace.

So;

The probabiility of the second player not getting an ace  and the first player getting an ace can be computed as;

P(\sim X_S| X_F) = 1 - P(X_S|X_F)

P(X_S|X_F) = \dfrac{P(X_SX_F)}{P(X_F)}

Let's determine the probability of getting an ace in the first player

i.e

P(X_F) = 1 - P(X_F^c)

= 1 -\dfrac{(^{2n-2}_n)}{(^{2n}_n)}}

= 1 - \dfrac{n-1}{2(2n-1)}

=  \dfrac{3n-1}{4n-2} --- (1)

To determine the probability of the second player getting an ace and the first player getting an ace.

P(X_sX_F) = \text{ (distribute aces to both ) and (select the left over n-1 cards from 2n-2 cards}P(X_sX_F) = \dfrac{2(^{2n-2}C_{n-1})}{^{2n}C_n}

P(X_sX_F) = \dfrac{n}{2n -1}---(2)

P(X_s|X_F) = \dfrac{2}{1}

P(X_s|X_F) = \dfrac{2n}{3n -1}

Thus, the conditional probability that the second player has no aces, provided that the first player declares affirmative is:

P(X_s^c|X_F) = 1- \dfrac{2n}{3n -1}

P(X_s^c|X_F) = \dfrac{n-1}{3n -1}

Therefore;

for n= 2

P(X_s^c|X_F) = \dfrac{2-1}{3(2) -1}

P(X_s^c|X_F) = \dfrac{1}{6 -1}

P(X_s^c|X_F) = \dfrac{1}{5}

P(X_s^c|X_F) =0.2

for n= 10

P(X_s^c|X_F) = \dfrac{10-1}{3(10) -1}

P(X_s^c|X_F) = \dfrac{9}{30 -1}

P(X_s^c|X_F) = \dfrac{9}{29}

P(X_s^c|X_F) =0.31

for n = 100

P(X_s^c|X_F) = \dfrac{100-1}{3(100) -1}

P(X_s^c|X_F) = \dfrac{99}{300 -1}

P(X_s^c|X_F) = \dfrac{99}{299}

P(X_s^c|X_F) =0.331

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