All categories

2 years ago

Choose the best response to the question below:

Mathematics

1 answer:

miss Akunina [59]2 years ago

6 0

Answer: Hi this is actually pretty easy and mark me a brainliest if correct it helps!

Step-by-step explanation: So this problem is showing A multiplied by B = AB squared 2, so this 2 * 3 = 6 because the star is another multiplication symbol

You might be interested in

X/2-14=-20 I tried on this one but I failed.

KengaRu [80]

Answer: I’m not going to tell u the answer hrhrhehehehehehrhehsnheaj

Step-by-step explanation:

-34 answer

6 0

3 years ago

Read 2 more answers

4. Solve the system using substitution.

Yuri [45]

Answer:

Step-by-step explanation:

-3+2=-1 and (9)- 8=1

3 0

2 years ago

A triangle of sides 15 cm 14 cm 13 cm prove

yarga [219]

Answer:

84 sq.m.

Step-by-step explanation:

Given : Sides of triangle are 13 cm,14 cm and 15 CM

To Find :find the area of the triangle

Solution:

We will use heron's formula :

Where

a = 13

b = 14

c = 15

Hence the area of the triangle is 84 sq.m.

Tip: use Heron's formula

6 0

2 years ago

Question 1 of 8

tekilochka [14]

Answer:

A, C,D,E,F

Step-by-step explanation:

6 0

2 years ago

Use the data in the table to answer the question. Citations are "speeding tickets." You may fill in the table to help you answer

Vikentia [17]

Answer:

Linear approximation is given by: $y = \frac{x}{5}+2$

Step-by-step explanation:

We are given the following information in the question:

Number of citations: 5 7.5 10 15 20

Outputs Residuals: 3 6 10 5 6

We have to find the linear approximation of the data that passes through the points (5, 3) and (20, 6).

Linear approximation is given by:

The equation of line is given by:

$(y-y_1) = \displaystyle\frac{y_2-y_2}{x_2-x_1}(x-x_1)$

where, $(x_1,y_1), (x_2.y_2)$ is the point through which the line passes.

The equation of line is:

$(y-3) = \displaystyle\frac{6-3}{20-5}(x-5)\\\\15(y-3)= 3(x-5)\\15y = 3x-15+45\\15y = 3x + 30\\y = \frac{x}{5}+2$

The above equation is the required linear approximation.

8 0

2 years ago