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Ganezh [65]
2 years ago
6

The moisture from when a plant is in a closed container

Biology
1 answer:
Olegator [25]2 years ago
5 0
The answer to this question is Condensation
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Molecular data can be used to assess relationships among the major groups of living organisms whose common ancestors lived milli
jek_recluse [69]

Answer: Faster-evolving gene sequences provide better data for comparisons among close relatives, whereas very slowly evolving sequences work best for distantly related tax.

4 0
3 years ago
Choose True or False.
Sindrei [870]

Answer:

TRUE

Explanation:

6 0
2 years ago
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g _______________ is the first amino acid in eukaryotic translation. Group of answer choices N-formylmethionine NONE OF THESE ar
kotegsom [21]

Methionine is the first Amino acid in eukaryotic translation.

<h3>What is Amino Acid?</h3>

Amino acid are building blocks of protein.

Amino acid are classified as either essential or non essential Amino acids.

Examples of Amino acid are methionine, lysine,leuscine and so on.

Methionine is a type of essential Amino acids that is found in eukaryotic animals.

It help in metabolism and health in species of animals.

Eukaryotic animals have tRNA that help to recognise the start of codons and it insert methionine and making it the first Amino acids.

Therefore, Methionine is the first Amino acid in eukaryotic.

Learn more about Amino acid from the link below.

brainly.com/question/1302816

8 0
1 year ago
why do all organisms take in matter and rearrange atoms through chemical reactions to form molecules essential for life?
Tom [10]
Cause living things can not directly use most of matter which they found in nature. For example carbon, all organism use carbon in complex structure, that is in compound or macromolecule(glucose,fructose,amino acid). we can not directly earn ATP from C which we found in soil/other sources.
3 0
3 years ago
A diploid nucleus of Drosophila melanogaster contains about 3.4 x 108 nucleotide pairs. Assume (1) that all nuclear DNA is packa
Olin [163]

Answer:

nucleosomes = 1.65 x 10^6

H2a = 3.3 x 10^6 molecules

H2b = 3.3 x 10^6 molecules

H3 = 3.3 x 10^6 molecules

H4 = 3.3 x 10^6 molecules

Explanation:

It was mentioned in the book Principles of Genetics  By D. Peter Snustad, Michael J. Simmons that in the nucleus of <em>D. melanogaster </em>there will be 1.65 x 10^6 nucleosomes and 3.3 x 10^6 molecules of every type of histone i.e. H2a, H2b, H3, and H4 present in it.

3 0
2 years ago
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