The solutions are (0, - 6) ,(7, 8)
The given system of equations is expressed as
y = x² - 5x - 6- - - - - - - - - - - - (1)
y = 2x - 6- - - - - - - - - - - (2)
We would apply the method of substitution by substituting equation 2 into equation 1. It becomes
x² - 5x - 6 = 2x - 6
x² - 5x - 6 = 2x - 6
x² - 5x - 2x - 6 + 6 = 0
x² - 7x = 0
x(x - 7) = 0
x = 0 or x - 7 = 0
x = 7 or x = 0
Substituting x = 0 into equation 2, it becomes
y = 2 × 0 - 6
y = - 6
Substituting x = 7 into equation 2, it becomes
y = 2 × 7 - 6
y = 14 - 6
y = 8
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Answer: 1. 13.752 2. 264
Step-by-step explanation:
hope this helps
Answer:
y=3x.........1
y=x^2-10.......2
substituting value of eq 1 to 2
3x=x^2-10
x^2-10-3x=0
x^2-3x-10=0
x^2-5x+2x-10=0
X(x-5)+2(x-5)=0
(x-5)(X+2)=0
then
X=5 or X=-2
again
y=??
when X=5
y=3×5=15
when X=-2
y=-6
|x+y| = |-8+(-13)| = |-8-13| = |-21| = 21
