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Nina [5.8K]
2 years ago
14

Which reaction will most likely take place based on the activity series? li > k > ba > ca > na > mn > zn >

cr > fe > cd > ni > h > sb > cu > ag > pd > hg > pt.
SAT
1 answer:
Ivenika [448]2 years ago
5 0

The only reaction that will most likely take place based on the activity series is; C: Ba + Na₂CO₃

<h3>Activity Series</h3>

From the activity series given, we can say that during a displacement reaction, the more reactive metal will always displace the lesser reactive metal from a compound.

Let us look at each of the given options;

A) Ag + FeCl₃

From the activity series, Silver(Ag) is less reactive than Iron(Fe) and as such Silver cannot displace iron from its' compound.

B) Zn + CaO

Zinc (Zn) is a less reactive metal than Calcium (Ca), so it cannot cannot displace Calcium from its' compound.

C) Ba + Na₂CO₃

Barium (Ba) is a more reactive metal than Sodium (Na), and therefore Barium will displace sodium from its compound in a displacement reaction.

D) Cr + KNO₃

Chromium (Cr) is a lesser reactive metal than Potassium (K), and it therefore cannot displace Potassium from its compound.

Complete question is;

Which reaction will most likely take place based on the activity series? Li > K Ba > CaNa > Mn > Zn > Cr> Fe> Cd Ni > H > Sb > Cu > Ag > Pd > Hg > Pt

A. Ag + FeCl₃

B. Zn + CaO

C. Ba + Na₂CO₃

D. Cr + KNO₃

Read more about Activity Series at; brainly.com/question/17469010

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\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac{t^2}t \sqrt{9 + 16t^2} \, dt

\displaystyle \int_C \frac xy \, ds = \int_1^4 t \sqrt{9 + 16t^2} \, dt

\displaystyle \int_C \frac xy \, ds = \frac1{32} \int_1^4 32t \sqrt{9 + 16t^2} \, dt

\displaystyle \int_C \frac xy \, ds = \frac1{32} \int_1^4 \sqrt{9 + 16t^2} \, d\left(9+16t^2\right)

\displaystyle \int_C \frac xy \, ds = \frac1{32} \cdot \frac23 \left(9+16t^2\right)^{\frac32}\bigg|_1^4

\displaystyle \int_C \frac xy \, ds = \frac1{48} \left(265^{\frac32} - 25^{\frac32}\right) = \boxed{\frac{265\sqrt{265}-125}{48}}

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