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m_a_m_a [10]
2 years ago
9

Calculate amount of solid (in grams) required to produce 250ml of a 1 in 10 solution.

Medicine
1 answer:
9966 [12]2 years ago
6 0

The amount of solid in grams required to produce 250ml of a 1 in 10 solution is 12.5 g

<h3>Preparation of solutions</h3>

Solutions are prepared when substances known as solutes are dissolved in another substance known as solvent.

In preparing solutions, the amount of solute required, concentration and volume of solution to be prepared is necessary.

  • Amount is the quantity of solute in grams or moles needed to be dissolved in a given solvent in order to prepare a solution of known concentration.
  • Amount in moles = mass/molar mass of solute
  • Concentration of a solution is the amount of solute per volume of solution
  • The volume of solution is measured in litres of millilitres

For example, to prepare a 250 mL of a 1 in 10 solution.

A 1 in 10 parts solution consists of 1 part stock solution and 9 parts solvent.

Concentration of the solution = 10%

% weight/volume = weight of solute/volume of  mL * 100

Let the weight of solute = x

5% = x/250 * 100

x = 5 * 250/100

x = 12.5 g

Therefore, amount of solid in grams required to produce 250ml of a 1 in 10 solution is 12.5 g

Learn more about percent concentration and amount at: brainly.com/question/17206790

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How much Dextrose 70% must be mixed with Dextrose 5% to prepare 1,000mL of Dextrose 20%? *
erastovalidia [21]

Answer:

231 ml

Explanation:

Let x represent the amo unt of Dextrose 70% in ml and y represent the amount of Dextrose 5% in ml needed to prepare 1,000mL of Dextrose 20%.

Since 1000 ml of Dextrose 20% is needed, hence:

x + y = 1000       (1)

Also 70% Dextrose is mixed with 5% dextrose to produce 20% dextrose. i.e.:

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We have to solve equations 1 and 2 simultaneously.

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subtract equation 1 from 3:

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Therefore 231 ml of Dextrose 70% must be mixed with 769 ml of Dextrose 5% to prepare 1,000mL of Dextrose 20%? *

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