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Lerok [7]
2 years ago
14

Company F sells fabrics known as fat quarters, which are rectangles of fabric created by cutting a

Mathematics
1 answer:
marysya [2.9K]2 years ago
8 0

Based on the information given, it should be noted that the mean and standard deviation of Y will be 0.4899 and 0.699 respectively.

<h3>Calculating the mean.</h3>

Based on the information given, it should be noted that the probability distribution for y will be:

Y                   0        1.         2

Probability 0.63.   0.25.   0.12

The mean of Y will be:

= (0 × 0.63) + (1 × 0.25) + (2 × 0.12)

= 0 + 0.25 + 0.25

= 0.49

The variance will be 0.4899. Therefore, the standard deviation will be:

= ✓0.4899

= 0.699

Learn more about mean on:

brainly.com/question/19243813

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-5,-6,0,6 which pair of numbers has a sum of zero
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I hope this helps :)

7 0
3 years ago
s(t) = 0.29t2 − t + 25 gallons per year (0 ≤ t ≤ 7), where t is time in years since the start of 2007. Use a Riemann sum with n
Sav [38]

Answer: The answer is 300 gallons.

Step-by-step explanation: Riemann sum is a method of calculating the total  area under a curve on a graph, which is also known as Integral.

To calculate that area, we divide it into a number of rectangles with one point touching the curve. The curve has a closed interval [a,b] that can be subdivided into n subintervals, each having a width of Δx_{k} = \frac{b-a}{n}

If a function is defined on the closed interval [a,b] and c_{k} is any point in [x_{k-1},x_{k}], then a Riemann Sum is defined as ∑f(c_{k})Δx_{k}.

For this question:

Δx_{k} = \frac{7-0}{5} = 1.4

Now, we have to find s(t) for each valor on the interval:

s(t) = 0.29t^{2} - t +25

s(0) = 25

s(1) = 24.29

s(2) = 24.16

s(3) = 24.61

s(4) = 25.64

s(5) = 27.25

s(6) = 29.44

s(7) = 32.21

Now, using the formula:

∑f(c_{k})Δx_{k} = 1.4(25+24.29+24.16+24.61+25.64+29.44+32.21)

∑f(c_{k})Δx_{k} = 1.4(212.6)

∑f(c_{k})Δx_{k} ≅ 300

With Riemann Sum, it is estimated the total country's per capita sales of bottled water is 300 gallons.

3 0
3 years ago
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