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quester [9]
3 years ago
8

What function corresponds to the ordered pairs shown in the table?

Mathematics
1 answer:
Anettt [7]3 years ago
6 0

well, we know it's a line, and to get the equation of any line all we need is two points, let's pick two from the table hmmmm say let's use (-3 , -7) and (3 , 11)

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{11}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{11}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-3)}}}\implies \cfrac{11+7}{3+3}\implies \cfrac{18}{6}\implies 3

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{3}(x-\stackrel{x_1}{(-3)}) \\\\\\ y+7=3(x+3)\implies y+7=3x+9\implies y = 3x+2

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The line 3x-8y=k cuts the x-axis and y- axis at the point A and B respectively. If the area of ∆AOB =12sq.units, find the value
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Given:

The equation is:

3x-8y=k

It cuts the x-axis and y- axis at the point A and B respectively.

The area of ∆AOB =12 sq.units.

To find:

The value of <em>k</em>.

Solution:

We have,

3x-8y=k

Substituting x=0 to find the y-intercept.

3(0)-8y=k

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y=\dfrac{k}{-8}

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Substituting y=0 to find the x-intercept.

3x-8(0)=k

3x-0=k

x=\dfrac{k}{3}

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The height of the ∆AOB is OB=\dfrac{k}{8} because distance cannot be negative and the base of the ∆AOB is OA=\dfrac{k}{3}. So, the area of the ∆AOB is:

A=\dfrac{1}{2}\times \dfrac{k}{8}\times \dfrac{k}{3}

A=\dfrac{k^2}{48}

It is given that, the area of ∆AOB = 12 sq.units.

\dfrac{k^2}{48}=12

k^2=576

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k=\pm 24

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