Answer:
B-malware
Explanation:
I do tech and i help work on computars.
Cleaning up a system helps clear up the space on the drives. It may also clear up processor usage, ram usage if you uninstall programs that automatically started when the system booted. You may also delete some unwanted programs in the process.
Answer:
<em>Continuous Process Production</em>
Explanation:
In a study on the relationship between industrial structure and performance, conducted by <em>Joan Woodward</em> from 1950 to 1959,
she classified technology into <em>three groups</em>:
- <em>Small batch and Unit technology </em>
- <em>Large batch and Mass production
</em>
- <em>Continuous process production
</em>
She came to a conclusion that the <em>continuous process production was the most complex</em> and unit technology as the least.
// Variable to keep track of array size
int length = 0;
// Array itself
int array[] = {};
// while loop will take input in the array until a negative number is entered
while(input>=0){
stdin = new Scanner(System.in);
array[length] = stdin;
length +=1;
}
// int variable to terminate while loop
int i =0;
// keep track of index of output array
int y =0;
while(arr[i] != length){
// making output array
int output[]={}; bool flag;
// put the element in out put array considering if it the desired one
output[y] = array [i];
// Now check if it was the desired?
for(int z=1;z<=length;z++){
if(array[i+z]!=output[y]){
flag = true;
}
else
{
output[y]=0;
y+=1;
}
if(array[i+z+1]=output[y] && flag == true){
output[y] = array[i];
y+=1;
}
}
//output the array
for(int o=0;o<y;o++)
System.out.println(output[o];
Answer:
Normalization of storage is a typical method of storing the floating point number by shifting the decimal after the first figure of the number such as 1101.101 is normalized to 1.101101x23.
If the number that is in hovering point representation has 1 sign bit, 3-bit exponent with a 4-bit significant:
whenever the storage is normalized, then the biggest positive floating spot number in 2`s and the complement notation is 0.11112 x 23 = 111.12 =7.5
If the storage is returned to normal, then the minimum positive floating point number is 0.12 x 2-4 =0.000012 =1/32 = 0.03125.
Explanation:
Whenever the floating figure is keyed into the computer memory, then the first bit will be the sign bit, the next 8 bits are for exponent and 23 bits are used for storing significand. The array of exponents is from -127 to 128. While Exponent 127 stands for 0 and positive figures can be represented by values bigger than 127. The biggest floating point number will be represented as 0.111111.... 1111x 211111111
