Question

In square ABCD, diagonals AC and DB intersect at point E, m∠EBC=(3x+9y)°, and m∠EAB=(5x+5y)°.

Answer 1

Answer:

Step-by-step explanation:

m∠EBC = 45°

3x + 9y = 45

Divide the entire equation by 3

x + 3y = 15 --------------------(I)

m∠EAB = 45

5x + 5y = 45

Divide the entire equation by 5

x +y = 9 -------------(II)

Multiply equation (II) by (-1)

(I)             x + 3y = 15

(II)*(-1)     - x -  y   = -9   {Now add}

                   2y   = 6

                     y = 6/2

                     y = 3

Plugin y = 3 in equation (I)

x + 3*3 = 15

x + 9 = 15

x = 15 - 9

x = 6