Answer:- B. No, because the corresponding congruent angles listed are not the included angles.
Explanation:-
Given:- ΔWXY and ΔBCD with ∠X ≅∠C, WX ≅ BC, and WY ≅ BD.
Now, look at the attachment
We can see that ∠X and ∠C are not included angles by the corresponding equal sides.
⇒ We cannot use SAS postulate to show ΔWXY ≅ ΔBCD .
⇒ B is the right option.
SAS postulate tells the if two sides of a triangle and their included angle is equal to the two sides of a triangle and their included angle of another triangle then the two triangles are congruent.
Answer:
10
Step-by-step explanation:
P(getting blue marbles) = 7/9
so;
x/45 = 7/9
x = 35
so the number of blue marbles is 35
45 - 35 = 10 red marbles
hope it helps .
all the best
The answer is simple to work out you do 3/8 + 1/3
but the denominators are different so you find the lowest common multiple in this case 24 .
the frection is now 9/24 + 8/24 this is 17/24
I changed the fraction by doing this 24(common multiple) divided by 8 (denominator) that's how I got it if you don't understand just ask me
Step-by-step explanation:
(2x³y^-4)^-2 = 1/(4x⁶y^‐8) = y⁸/(4x⁶)
1/(8x⁵y^-7) = y⁷/(8x⁵)
4x^-9y⁴ = 4y⁴/x⁹
so, the whole expression is then
y⁸/(4x⁶) × y⁷/(8x⁵) × 4y⁴/x⁹
4y¹⁹/(32x²⁰) = y¹⁹/(8x²⁰)
so, D is the correct answer.