Question

Solve the equation by using quadratic formula . Show your work! Answer maybe in radical or decimal form .

Answer 1

Answer:

$x_1=\frac{-2+\sqrt{14}}{2}\approx 0.871,x_2=\frac{-2-\sqrt{14}}{2}\approx-2.871$

Step-by-step explanation:

$2x^2+4x-5=0$

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-4\pm\sqrt{4^2-4(2)(-5)}}{2(2)}$

$x=\frac{-4\pm\sqrt{16+40}}{4}$

$x=\frac{-4\pm\sqrt{56}}{4}$

$x=\frac{-4\pm2\sqrt{14}}{4}$

$x=\frac{-2\pm\sqrt{14}}{2}$

$x_1=\frac{-2+\sqrt{14}}{2}\approx 0.871,x_2=\frac{-2-\sqrt{14}}{2}\approx-2.871$