ur answer to this question is -6
13406=thirteen thousand, four hundred six.
Given:
year 0 - 2005 : 90,000
year 1 - 2006 : 91,200
91,200 - 90,000 = 1,200
1,200 / 90,000 = 0.013
90,000 (1+0.013)^1 ⇒ 90,000 (1.013)^1 = 91,170 OR 91,200
The best representation of the relationship between x and f(x) is choice 2.
f(x) = 90(1.013)x
15 rounded to the nearest hundred is 100 or one hundred
The confidence interval for the proportion of students attending a football game is [0.6592, 0.7044].
Confidence interval can be calculated by below formula

where the left part is the lower interval and right side is the higher interval.
Pcap = 750/1100
Pcap = 0.6818
Again to calculate
, as we know that the level of confidence is 90 percent so its value will be 1.645
now putting the values on the both side we can get ,
0.6818 - 1.645 x 0.014 < p < 0.6818 + 1.645 x 0.014
0.6818 - 0.023 < p < 0.6818 + 0.023
0.6588 < p < 0.7048
the nearest value is [0.6592, 0.7044]
Hence the confidence interval for the proportion of students attending a football game is [0.6592, 0.7044]
To know more on confidence interval, visit here
brainly.com/question/13067956
#SPJ4